Graph the image of kite QRST after a reflection over the line y= –x.
The required image of kite QRST after a reflection over the line y= -x has shown in the attached graph.
point Q (3,10)
point R (-1,9)
point S (3,7)
point T (7,9)
What is a graph?A graph can be defined as a pictorial representation or a diagram that represents data or values.
What is a reflection over the line y = −x?Reflection over the y = −x is defined as reflecting a point across they = −x, the x-coordinate and y-coordinate change places, and t the line y = x is the coordinates (y, x). the line y = -x is the coordinates (-y, -x).
Here point Q (−7,5) reflected across the line y = -x will become (3,10).
Similarly
point R (-1,9)
point S (3,7)
point T (7,9)
Therefore, the required image of kite QRST after a reflection over the line y= -x has shown in the attached graph.
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Given AB with A(8, -4) and B(-6, 11), if P partitions AB such that the ratio of AP to AB is 2:7, find the coordinates of P
PLEASE SOLVE ITS FOR A TEST
Answer:
[tex]3\sqrt{3}[/tex]
Step-by-step explanation:
Find the functions and their domains. (enter the domains in interval notation.) f(x) = x 1 x , g(x) = x 14 x 2
Functions and their domains of all the subparts are:
(A) (fog)(x) and the domain is [tex](-\infty, \infty)[/tex].(B) (gof)(X) and the domain is [tex](-\infty, \infty)[/tex].(C) (fof)(x) and the domain is [tex](-\infty, \infty)[/tex].(D) (gog)(x) and the domain is [tex](-\infty, \infty)[/tex].What are functions?A function is an expression, rule, or law in mathematics that defines a relationship between a dependent thing (the independent variable) and another variable (the dependent variable). Functions are common in mathematics and are required for the formulation of physical relationships in the sciences.So,
(A) (fog)(x) and domain:
[tex](f \circ g)(x)=f(g(x))=(g(x))^2+g(x)=\left(x^2+14 x+2\right)^2+x^2+14 x+2\\=x^4+28 x^3+200 x^2+56 x+4+x^2+14 x+2=x^4+28 x^3+201 x^2+70 x+6[/tex]
The domain of (fog)(x) is the collection of domain values for g(x) with range values in the domain of f(x).
Because both functions are polynomials, the domain is [tex](-\infty, \infty)[/tex].
(b) (gof)(X) and domain:
[tex](g \circ f)(x)=g(f(x))=(f(x))^2+14(f(x))+2=\left(x^2+x\right)^2+14\left(x^2+x\right)+2\\=x^4+2 x^3+x^2+14 x^2+14 x+2=x^4+2 x^3+15 x^2+14 x+2[/tex]
The domain name is [tex](-\infty, \infty)[/tex] because this is a polynomial composition.
(c) (fof)(x) and domain:
[tex]\begin{aligned}&(f \circ f)(x)=f(f(x))=(f(x))^2+f(x)= \\&\left(x^2+x\right)^2+x^2+x=x^4+2 x^3+x^2+x^2+x=x^4+2 x^3+2 x^2+x\end{aligned}[/tex]
Because this is a polynomial composition, the domain is [tex](-\infty, \infty)[/tex].
(d) (gog)(x) and domain:
[tex](g \circ g)(x)=g(g(x))=(g(x))^2+14(g(x))+2=\left(x^2+14 x+2\right)^2+14\left(x^2+14 x+2\right)+2\\=x^4+28 x^3+200 x^2+56 x+4+14 x^2+196 x+28+2=x^4+28 x^3+214 x^2+252 x[/tex]
Because this is a polynomial composition, the domain is [tex](-\infty, \infty)[/tex].
Therefore, functions and their domains of all the subparts are:
(A) (fog)(x) and the domain is [tex](-\infty, \infty)[/tex].(B) (gof)(X) and the domain is [tex](-\infty, \infty)[/tex].(C) (fof)(x) and the domain is [tex](-\infty, \infty)[/tex].(D) (gog)(x) and the domain is [tex](-\infty, \infty)[/tex].Know more about functions here:
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The complete question is given below:
Find the functions and their domains. (enter the domains in interval notation.)
[tex]f(x)=x^2+1 x, g(x)=x^2+14 x+2[/tex]
(a) (fog)(x) and domain
(b) (gof)(X) and domain
(c) (fof)(x) and domain
(d) (gog)(x) and domain
The following are the amounts of radiation received at a greenhouse.
6.1 6.8 8.7 9.0 10.2 10.3 10.6 10.8 10.9 11.0 11.1 11.5 11.7 12.2 13.4
find the sample range.
The given data be 6.1, 6.8, 8.7, 9.0, 10.2, 10.3, 10.6, 10.8, 10.9, 11.0, 11.1, 11.5, 11.7, 12.2, 13.4 then the sample range is 7.3.
What is meant by sample range?A well-liked and straightforward method for comparing the variability of various data distributions is the sample range. The formula for the sample range is the greatest value minus the smallest value. It is based on two values in a data set: the maximum and minimum.
The probability distribution of a statistic that is acquired by repeated sampling of a particular population is called the sampling distribution. It outlines a variety of potential possibilities for a statistic, such as the mean or mode of a population's mean or mode of some variable.
Arrange all values in your information set from low to high.
Subtract the lowest value from the highest value.
Let the given data be 6.1, 6.8, 8.7, 9.0, 10.2, 10.3, 10.6, 10.8, 10.9, 11.0, 11.1, 11.5, 11.7, 12.2, 13.4
13.4 - 6.1 = 7.3
Therefore, the sample range is 7.3
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Find the linear function represented by the graph.
The slope of the line is
.
The y-intercept of the line is at
.
What linear function is represented by the graph?
Step-by-step explanation:
photo please ......................
Answer:
Step-by-step explanation:
need to see the graph
A flagpole makes a 15-foot long shadow. The angle of elevation with the end of the shadow and the ground
makes a 65° angle. What is the height of the flagpole?
Answer:
12.5988 feet.
Step-by-step explanation:
Length of shadow = 15 feet.
Height of flagpole = A.
We know the angle of elevation is 40∘. Using this angle and the tangent ratio, we can find A.
Hope this helps! :)
in 2018, the population density in singapore was 21,400 residents per square mile. what is the population density of singapore in residents per square kilometer? (note that 1 mi
The population density of Singapore in residents per square kilometer is 8266.12 per square kilometer
What is Population Density ?
The ability to compare settlement intensities across geographical areas is made possible by population density. The number of persons per square mile of land area is the most common way to express population density in the United States.The given parameters are
Number of people = 21400 residents
Area = 1 mi²
Convert the square mile to square kilometer
1 x 1.609² = 2.588881 Km²
Population density = Number of residents ÷ area
Population density = 21400 ÷ 2.588881
Population density = 8266.12 per square kilometer
Therefore, the population density of Singapore in residents per square kilometer is 8266.12 per square kilometer
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Mike bought yards of ribbon. Jim bought four times the amount of ribbon that Mike bought. How many yards of ribbon did Jim buy?
Answer:
four times the amount of mike
Step-by-step explanation:
When adding 7 to -15 using a number line, which direction would you move on the number line from -15?
Answer: To the right
Step-by-step explanation:
The negatives on a number line are on the left side and the positives on the right.
Step-by-step explanation: educated guess
PLS HELPPP
identify the graph of the ellipse.
[tex]\frac{(x-3)^{2} }{16} +\frac{y-4^{2} }{9} =1[/tex]
The correct graph of the ellipse is identified and attached below.
Given the equation is (x₋3)²/16 ₊ (y₋4)²/9 = 1
step 1: identify the center (h,k) of the ellipse in standard form:
(x₋h)²/a² ₊ (y₋k)²/b² = 1
In the standard form of an ellipse, notice that there is a minus sign in front of the h and k.
In our equation (x₋3)²/16 ₊ (y₋4)²/9 = 1 , we have:
h = 3 and k = 4
Therefore, center (h,k) = (3,4)
Step 2: Identify the orientation by determining the major axis and minor axis in (x₋h)²/a² ₊ (y₋k)²/b² = 1
if a>b, the major axis is horizontal and the minor axis is vertical, making the ellipse a horizontal ellipse.
if a<b, the minor axis is horizontal and the major axis is vertical, making the ellipse a vertical ellipse.
For (x₋3)²/16 ₊ (y₋4)²/9 = 1
a² = 16, a = 4 and b² = 9 , b = 3
so, 4>3, the major axis is horizontal and the minor axis is vertical, making the ellipse a horizontal ellipse.
Step 3:
Plot the co-vertices along the minor axis and the vertices along the main axis (endpoints). No matter which way around, draw points a horizontal distance of a to the left and right from the center and points b above and below the center.
Therefore the vertices are marked along the major axis.
vertices are (3,7) and (3,1)
and co vertices are marked along the minor axis
co vertices are (₋1,4 ) and (7,4)
step 4: connect the vertices and co vertices making a smooth horizontal ellipse.
Hence a horizontal ellipse is made.
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PLEASE SHOW WORK
Simplify the expression
3/2(4f-10)
Answer:
6f-15
Step-by-step explanation:
First distribute 3/2.
3/2(4) =6
3/2(-10) =15
So, the answer should be 6f-15.
Let me know if you do not understand or need further explanation :)
The parties to a sales contract have stipulated that a specific sum be paid by any party breaching said contract, this sum is called?
This type of sum is Liquidated damages.
What is Liquidated damages?Liquidated damages are presented in certain legal contracts as an estimate of otherwise intangible or hard-to-define losses to one of the parties.
As per the given situation we have
parties to a sales contract have stipulated that a specific sum be paid by any party
Liquidated damages occur in such a situation.
The amount of damages that the parties estimate and agree upon at the time of the contract for a breach of the agreement by either party is referred to as liquidated damages.
Regardless of the actual cost of any potential damages due to the breach of the contract, this amount becomes due immediately.
According to Section 74 of the Indian Contract Act, 1972, if parties agree a sum to be paid as damages or a penalty to be imposed for a breach, the harmed party is only entitled to that sum or penalty and no other higher or lesser sum.
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Help, please.
I’m not sure how to do it, but it’s part of a puzzle.
Answer:
x = 14 y = 59
Step-by-step explanation:
the angle (5x - 11) is equal to the angle (3x + 17) and 3x+ 17 is equal to y
5x - 11 = 3x + 17
5x - 3x = 17 + 11
2x = 28
x = 28/2
x = 14
3x+17 = y
3(14) + 17 = y
y = 59
Step-by-step explanation:
Fact 1: Alternate angles are equal.
Angles, (5x-11)° and (3x+17)° are ALTERNATE angles and so,
(5x-11)° = (3x+17)°
5x - 3x = 17 + 11
2x = 28
x = 28 ÷ 2
x = 14
NB: x does NOT have the degree sign because it's NOT an angle on its own, but rather within the bracket/part of the calculation to get the angle degree.
Fact 2: Opposite angles are equal.
Y° and (3x+17)° are OPPOSITE angles
y = (3x+17)°
y = (3x14) + 17
y= 42 + 17
y = 59°
Hope this helps!
Express each of the following in terms of power of 10: i. 10 ii 1000000 iii 90000
The numbers in terms of power of 10 is;
(i) [tex]10^{1}[/tex]
(ii) [tex]10^{6[/tex]
(iii) [tex]9 * 10^{4}[/tex]
Here,
Given numbers are;
i. 10
ii 1000000
iii 90000
We have to find in terms of power of 10.
What is Powers of a number?
The power of a number says how many times to use the number in a multiplication. Powers are also called Exponents or Indices.
Now,
Given numbers are;
i. 10
ii 1000000
iii 90000
We can write in terms of power of 10 as;
(i) 10 = [tex]10^{1}[/tex]
(ii) 1000000 = [tex]10^{6[/tex]
(iii) 90000 = [tex]9 * 10^{4}[/tex]
Hence, The numbers in terms of power of 10 is;
(i) [tex]10^{1}[/tex]
(ii) [tex]10^{6[/tex]
(iii) [tex]9 * 10^{4}[/tex]
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draw a rectangle. label the height as 5 cm and the width as 2x + 8. if the area is 80 cm^2 write an equation to find the value of x. then find the width of the rectangle
Answer:
16cm
Step-by-step explanation:
The area of a 2d figure is w x h. We know the area, a, is 80cm^2, the height, h, is 5, and the width, w, is 2x + 8.
Since we are solving for x, we want to isolate the variable.
5 x 2x + 8 = 80
80/5 = 2x + 8
We can now solve for x.
80/5 = 2x + 8
16 = 2x + 8
16 - 8 = 2x + 8 - 8
8 = 2x
8/2 = 2x/2
4 = x
We aren't done, we still need to solve for w, where we now know x = 4
w = 2x + 8
w = 2(4) + 8
w = 8 + 8
w = 16
I need to find the following limits
The solution are-
(a) lim h (x) = -2
x → -2⁻
(b) lim h (x) = -2
x → -2⁺
(c) lim h (x) = -2
x → -2
What is defined as the limits of the functions?A limit describes the value which a function approaches as its inputs get increasingly closer to a certain number.
The concept of a limit is at the heart of all calculus.
(a) lim h (x) = -2
x → -2⁻
Put x = 2 at the place of x in h(x).
This limit is called the left hand limit of the function as there is negative sign over 2.
(b) lim h (x) = -2
x → -2⁺
Put x = 2 at the place of x in h(x).
This limit is called the right hand limit of the function as there is positive sign over 2.
(c) lim h (x) = -2
x → -2
Put x = 2 at the place of x in h(x).
This limit exists just at x = 2.
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How do you calculate the X and Y coordinates of the vertex when the equation is in standard form?
If the quadratic is y = a*x^2 + b*x + c
the coordinates of the vertex are:
x = -b/2a
y = (1/2a)*( -0.5*b^2 + c)
How to find the coordinates of the vertex?For a quadratic equation in standard form:
y = a*x^2 + b*x + c
The x-value of the vertex is given as:
x = -b/2a
Once we get the x-value of the vertex, we can get the y-value by evaluating the quadratic equation in x = -b/2a, we will get:
y = a*(-b/2a)^2 + b*(-b/2a) + c
y = b^2/(4a) - b^2/2a + c = (1/2a)*(b^2/2 - b^2 + c)
y = (1/2a)*( -0.5*b^2 + c)
Then the coordinates of the vertex are:
x = -b/2a
y = (1/2a)*( -0.5*b^2 + c)
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63) Julia has 1/3 many stamps as Robert and also 2/3
as many stamps as
Erin. If Erin has 36 stamps, what is the total number of stamps that
the 3 children have?
Answer: The total number of stamps is 132.
Step-by-step explanation:
We know that Erin has 36 stamps.
Given that information, we can calculate how many stamps Julia has which is 2/3 as many stamps as Erin.
2/3 * 36 = 24
Julia has 24 stamps.
Julia also has 1/3 as many stamps as Robert.
24 = 1/3 * Robert
Robert = 72 stamps
Add the three numbers together to get your final answer
24 + 72 + 36 = 132
Describe how to show 5-4 subtraction problem on a number line.
Answer: By having the arrow going to the left of the number line
Step-by-step explanation:
When subtracting, you always go to the left of the number line. Just like how you go to the right when adding. also having the line going from 5 to 1.
Un automóvil recorre 1122.4 km con 80 litros de gasolina ¿cuántos kilómetros recorre con 16 litros de gasolina?
The automobile covers 224.48 km.
This problem can be solved by using the unitary method.
In this method we calculate the value for a unit quantity and then multiply it with the desired number for which we want to calculate.
Here it is given that a automobile covers 1122.4 km with 80 liters.
For 1 liter of gasoline distance covered = [tex]\frac{1122.4}{80}[/tex]
= 14.03 km
So, for 16 liters of gasoline distance covered will be = 16× 14.03
= 224.48 km
Therefore the automobile covers 224.48 km for 16 liters of gasoline.
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Find the difference of -6-(-7)
Answer:
1
Step-by-step explanation:
When you simplify, the answer is 1.
Answer:
1
Step-by-step explanation:
the following are amounts of total snow falls (in inches) in different midwestern cities in the united states in a certain year: 20 40 31 7 15 29 25 20 17 32 28 12 34 29 20 17 33 23 find the sample mean.
The sample mean of the given data is 24.
What do we mean by mean?In mathematics, particularly statistics, there are several types of means. Each mean is used to summarize a specific set of data, often in order to better understand the overall value (magnitude and sign) of a given data set.The arithmetic mean, also known as "arithmetic average," of a data set is a measure of the central tendency of a finite set of numbers: specifically, the sum of the values divided by the number of values.To find the mean:
Mean = sum of terms/number of termsMean = 432/18Mean = 24Therefore, the sample mean of the given data is 24.
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what is 6x7(8-0)3+5=
Answer:
1013
Step-by-step explanation:
(6)(7)(8−0)(3)+5
=42(8−0)(3)+5
=(42)(8)(3)+5
=(336)(3)+5
=1008+5
=1013
Consider the pair of points below.
(4, 5)
(5, 1)
Find the slope of the line passing through the pair of points
m =
The slope of the line for the pair of points (4,5) and (5,1) is m= -4.
As given in the question,
Let the pair of points of the line are
(x₁ ,y₁) = (4, 5)
(x₂ , y₂) = (5,1)
Slope of the line passing through the pair of points (x₁ ,y₁) = (4, 5) and
(x₂ , y₂) = (5,1) is given by
m = (y₂ -y₁) / (x₂ - x₁)
⇒ m = (1-5) / (5 -4)
⇒ m = -4
Therefore, the slope of the line for the pair of points (4,5) and (5,1) is
m= -4.
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complete the square: (x-7)^2 = 8
Quadratic equations are all those equations that can be reformulated in a standard format (αx² + bx + c(=0) where the value of x is unknown and the values of the coefficients (a, b and c) are unknown.
These equations can always be solved using the quadratic formula, although sometimes it is also possible to use factorization or isolation of variables.
[tex]\large\displaystyle\text{$\begin{gathered}\sf (x-7)^{2}=8 \end{gathered}$}[/tex]Expand squared
[tex]\large\displaystyle\text{$\begin{gathered}\sf (x-7)(x-7)=8 \end{gathered}$}[/tex]It is distributed
[tex]\large\displaystyle\text{$\begin{gathered}\sf x(x-7)-7(x-7)=8 \end{gathered}$}[/tex][tex]\large\displaystyle\text{$\begin{gathered}\sf x^{2} -7x-7(x-7)=8 \end{gathered}$}[/tex][tex]\large\displaystyle\text{$\begin{gathered}\sf x^{2} -7x-7x+49=8 \end{gathered}$}[/tex]Combine like terms.
[tex]\large\displaystyle\text{$\begin{gathered}\sf x^{2} -14x+49=8 \end{gathered}$}[/tex]Move terms to the left
[tex]\large\displaystyle\text{$\begin{gathered}\sf x^{2} +14x+49-8=0 \end{gathered}$}[/tex]Subtract the numbers
[tex]\large\displaystyle\text{$\begin{gathered}\sf x^{2} -14x+41=0 \end{gathered}$}[/tex]Use the quadratic formula.
[tex]\large\displaystyle\text{$\begin{gathered}\sf x=\frac{-b\pm\sqrt{b^{2}-4ac } }{2a} \end{gathered}$}[/tex]
In standard form we identify "a", "b" and "c" from the original equation and add to the quadratic formula.
a = 1b = -14c = 41[tex]\large\displaystyle\text{$\begin{gathered}\sf x=\frac{-(-14)\pm\sqrt{(-14)^{2}-4\cdot1\cdot41 } }{2\cdot1} \end{gathered}$}[/tex]
Simplify
Calculate the exponentmultiply the numbersSubtract the numbersCalculate the square rootmultiply the numbersWe multiply the numbers[tex]\large\displaystyle\text{$\begin{gathered}\sf x=\frac{14\pm4\sqrt{2} }{2} \end{gathered}$}[/tex]
Separate equations
To solve for the unknown variants, we split the equation into two: one with a plus sign and the other with a minus sign.
[tex]\large\displaystyle\text{$\begin{gathered}\sf x=\frac{14+4\sqrt{2} }{2} \end{gathered}$}[/tex]
[tex]\large\displaystyle\text{$\begin{gathered}\sf x=\frac{14-4\sqrt{2} }{2} \end{gathered}$}[/tex]
Solve
Order and isolate the variant to find each solution.
[tex]\large\displaystyle\text{$\begin{gathered}\sf x=7+2\sqrt{2} \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x=7-2\sqrt{2} \end{gathered}$}[/tex]
[tex]\red{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\blue{Answer \ \ \longmapsto \ \ x=7\pm2\sqrt{2} }} \end{gathered}$}}}[/tex]
Learn more at:https://brainly.com/question/22842654SkandarAlyssa spent 365 hours commuting on the train over the course of 54 days.if she rode the same amount of time per day , approximately how many hours did she spend on the train per day.
Approximately 6.8 hours Alyssa spends on the train per day.
Given that, Alyssa spent 365 hours commuting on the train over the course of 54 days.
We need to find the number of did Alyssa spend on the train per day.
What is an equation?In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
Let the number of hours Alyssa spends on the train per day be x.
Now, x=365/54
=6.759≈6.8 hours
Therefore, approximately 6.8 hours Alyssa spends on the train per day.
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solve y= 4x + rz + 6 for x
Step-by-step explanation:
y=4x+rx+6
y-6=4x+rxy−6=4x+rx Subtract \ 6 \ from \ both \ sidesSubtract 6 from both sides
y-6=x(4+r)y−6=x(4+r) Factor \ out \ the \ common \ term \ xFactor out the common term x
\dfrac{y-6}{4+r} =x
4+r
y−6
=x Divide \ both \ sides \ by \ 4+rDivide both sides by 4+r
38. Автор, проверяя набранные на компьютере страницы будущей
книги, обнаружил опечатки, данные о которых приведены в
таблице:
Номер страницы
1 2 3 4 5 6 7 8
Число опечаток 0 1 0 2 1 2 4 3
Верно ли, что стандартное отклонение данных этой выборки
не больше 1?
Answer:
the answer is clear
Step-by-step explanation:
you have to get the answer by completing the answer
Help
Please urgent please help please urgent quick mathematical question
The area occupied by the photograph in terms of x described by the quadratic equation A = x² - 20 · x + 100.
How to derive the expression for the area occupied by the photograph
Both the backing card and the photograph are represented by two concentric squares, the area of the square is equal to the square of the side length. The expression for the area occupied by the photograph is described by the following polynomial:
A = l²
A = (x - 10) · (x - 10)
A = (x - 10)²
A = x² - 20 · x + 100
The area occupied by the photograph in terms of x described by the quadratic equation A = x² - 20 · x + 100.
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