Which number would be found on the number line between 0 and -1
Answer: -.5 OR -.1, -.2, -.3, -.4, -.5, -.6,-.7,-.8,-.9
Step-by-step explanation: The simple answer is -.5, it is right in the middle of 0 and -1. The answer number is everything in between.
Need help on this question ASAP please
The equations ordered from the least to greatest is
y = (-3/4)x + 2
y - 3 = 1/2(x - 4)
3x - 4y = 7
y = 12(x - 19) + 5
Order of equationsFrom the question, we are to order the equations from least to greatest by the value of the slope
The given equations are
y = (-3/4)x + 2
3x - 4y = 7
y = 12(x - 19) + 5
y - 3 = 1/2(x - 4)
To determine the slopes of the line, we will compare the equations to the general form of the equation of a line
The general form of the equation of a line is
y = mx + b
Where m is the slope
and b is the y-intercept
y = (-3/4)x + 2By comparison,
m = -3/4
∴ Slope = -3/4
3x - 4y = 7First, rearrange
3x - 7 = 4y
4y = 3x - 7
y = (3/4)x - 7/4
By comparison,
m = 3/4
∴ Slope = 3/4
y = 12(x - 19) + 5First, simplify
y = 12x - 228 + 5
y = 12x - 223
By comparison,
m = 12
∴ Slope = 12
y - 3 = 1/2(x - 4)
First, simplify
y - 3= (1/2)x - 2
y = (1/2)x -2 + 3
y = (1/2)x + 1
By comparison,
m = 1/2
∴ Slope = 1/2
Now,
The slopes ordered from the least to greatest is
-3/4 < 1/2 < 3/4 < 12
Thus,
The equations ordered from the least to greatest is
y = (-3/4)x + 2
y - 3 = 1/2(x - 4)
3x - 4y = 7
y = 12(x - 19) + 5
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11. The following describes the United States nuclear stockpile from
1944 to 1974. From 1944 to 1958, there was a gradual increase in the
number of warheads from 0 to about 5000. From 1958 to 1966, there
was a rapid increase in the number of warheads to a maximum of
about 32,000. From 1966 to 1970, there was a decrease in the number
of warheads to about 26,000. Finally, from 1970 to 1974, there was
a small increase to about 28,000 warheads. Sketch a graph of the
function.
10.
nxhudkdodisuhaiioavsbos
Help !!! With this please !!!
Answer: $48.17
Step-by-step explanation:$148.68-$24.32= $124.36
$124.36-$37.53= $86.83
$135 -$86.83=$48.17
So he needs forty-eight dollars and 17 cents.
When the relationship between the unit of measurement of a scale (strength) and an outcome (pounds lifted) can be described by a linear equation y = a bx, the scale is said to have what property?
When the relationship between the unit of measurement of a scale (strength) and an outcome (pounds lifted) can be described by a linear equation y = a bx, the scale is said to have a property of equal intervals.
What are equal intervals?Equal intervals denote that the variations between numbers (units) are the same anywhere on the scale (e.g., the difference between 4 and 5 is the same as the difference between 76 and 77). The difference between two successive categories is equal in an equal interval. Temperature measured in Fahrenheit, for example, has equal intervals; that is, the difference between 30 and 31 degrees is one degree, and the difference between 100 and 101 degrees is one degree.When the relationship between a scale's unit of measurement (strength) and a consequence (pounds lifted) can be described by the linear equation y = a bx, the scale is said to possess an equal intervals property.Therefore, when the relationship between the unit of measurement of a scale (strength) and an outcome (pounds lifted) can be described by a linear equation y = a bx, the scale is said to have a property of equal intervals.
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Please help me answer all these 4 math questions! It is 8th-grade beginner level.
I will give Brainliest to the 1st one to answer ALL 4 questions and will give 100 points in this problem, giving people 50 points when they answer.
Answer:
Simplify the expression, Your answer would be :
1. [tex]\frac{9d}{e^{6} }[/tex]2. [tex]6d^{3}e[/tex]3.[tex]12de^{6}[/tex]Step-by-step explanation:
And to find the Value of the following expression, Your answer would be :
[tex]\frac{36}{11}[/tex]hopefully this helps you ! ~
Please help !!! , I have 8 mins left on the clock .
Express the relation below as a set of ordered pairs.
By critically observing the graph shown above, the set of ordered pairs include the following:
(-1, 5)(4, -3)(-5, -3)(0, 5)(-4, 5)What is a graph?A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a cartesian coordinate, which are the x-axis and y-axis.
What is an ordered pair?An ordered pair can be defined as a pair of two elements that are typically written in a fixed order within parentheses as (x, y), which represents the x-axis (abscissa) and the y-axis (ordinate) on a coordinate plane.
By critically observing the graph shown above, we can logically deduce that the set of ordered pairs include the following:
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x^5y^5z^3 =?
A. bases are different, so this can't be done.
B. xy5z3
C. (xy)5z3
To simplify the indices expression x⁵y⁵z³, we can conclude that; A. bases are different, so this can't be done.
How to simplify Indices?We want to simplify the indices given as;
x⁵y⁵z³
Now, we can see that the bases are different and as such it means they cannot be simplified using laws of indices on the exponents.
This is because when the bases are different, the expression cannot be factored with the exponents being added, subtracted, divided or multiplied.
Thus, we will conclude that the bases are different, so this can't be done.
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1. Determine whether each relation is a function.
((3, 2), (1,2), (4,3), (6, -2)}
domain = { 3,1,4,6} and range = { 2, 2 , 3 ,-2} are each relation is a function.
Describe domain.
The term "domain," which is specific to the internet, can apply to both the structure of the internet and the organization of a company's network resources. A domain is typically a sphere of knowledge or a governing region.Describe Range?
Range is the difference between the largest and lowest values in a dataset in statistics and mathematics. One indicator of data dispersion is the range.
function = ((3, 2), (1,2), (4,3), (6, -2)}
domain = { 3,1,4,6}
range = { 2, 2 , 3 ,-2}
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on the next play, the team gained 5 yards and then lost 6 yards. what is the total change in yards? 5- blank
= 5 + blank
= blank
help me schools tomorrow
here were 34 bales of hay in the barn. Dan stacked more bales in the bar
today. There are now 64 bales of hay in the barn. How many bales did he store in the barn?
Solve for x in the diagram below.
X =
хо
100°
3x°
Answer:
20
Step-by-step explanation:
the line equals 180 degrees total.
so subtract the angle we already know from the total...
180- 100=80
then, make an equation with the last two variables since we know both of them added together should equal 80
80=x +3x
Combine like terms
80=4x
Divide by 4
20=x
The sides of a rectangle are x and 3 - 2x. Express the rectangle's area as a function of x. Express the rectangle's perimeter as a function of x. Explain why x cannot equal 2.
Answer: It is 3.5
Step-by-step explanation:
I think this because 2/2x=3/2=1.5 but you have 2 left to add which=3.5
11. A population of bacteria triples every week in a laboratory. The number of
bacteria is modeled by the expression 900 3*, where x is the number of weeks
after a scientist measures the population size. When x = -2, what does the value
of the expression represent?
Answer:
Step-by-step explanation:
Let x represent the number of weeks a population of the bacteria increases. Then, we have the number of bacteria is molded by the expression of 900*3^x. By, the given expression and when we assigned a value of x=2. Then we have 900*3² .
Kyle found the product of two rational expressions and identified the excluded values of the expression. However, he made a mistake in his work and included an extra number in his list of excluded values. His work is shown below.
Select the step where Kyle made his first mistake. Then select the number that should not be included in the list of excluded values.
Answer:
Step-by-step explanation:
Mistake in step 3 the (2x+1) and the (x-1) both cancel out but the other binomials (x + 3) and (x - 3) are different so don't cancel out.
Step 3 should be 3(x-3) / 4(x+3)
3 should not be an excluded value.
Which scales of data measurement are associated with quantitative data? interval and ratio ratio and nominal ordinal and interval nominal and ordinal
Interval and ratio scales of data measurement are associated with quantitative data.
Data measurement:- Data measurement is the way in which data can be subcategorized to analyze the data properly. Data can be classified into two types-
Quantitative data:- The data, which can be measured with numbers is called as quantitative data. Ex: duration, speed etc. This kind of data can be again subcategorized into two types-Discrete:- The data, which is of whole number, that can't be broken. Ex: a number of items.Continuous:- The data, which can be broken. Ex: height, weight etc. This type of data can be measured using interval and ratio measurement scales.Qualitative data:- The data, which is non-numerical value and categorical is called as qualitative data. Ex: yes, no responses or eye color etc. This type of data can be measured using nominal and ordinal measurement scales.Thus we can conclude that, Interval and ratio scales of data measurement are associated with quantitative data.
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Which of the following options are examples of how you can name the angle?
Answer:
∠T and ∠STP
Step-by-step explanation:
You can name an angle by their middle vertex letter which, in this case, is T.
And you can name an angle using the three letters provided. P, T, and S are the three letters provided. However, the vertex letter always has to be in the middle. So, it could be ∠STP or even ∠PTS.
Let me know if you don't understand or need more explanation.
Multiplying and dividing Decimals.
−6.87(−2.65).
Answer:18.2055
Step-by-step explanation:−6.87(−2.65)=−6.87*−2.65=18.2055
During the school year, each student planted
1.2 x 10^2 flowers as part of a community
service project. If there are 1.5 x 10³
students in the school, how many flowers did
they plant in total?
Answer:
18000
Step-by-step explanation:
We can multiply the number of students by the number of flowers per student.
[tex](1.2 \times 10^2)(1.5 \times 10^3) \\ \\ =(1.2)(1.5)(10^5) \\ \\ =1.8 \times 10^5 \\ \\ =18000[/tex]
HELPPPPP PLEASE. PLEASE TELL ME THE BLANKS IN ORDER.
(write each as an algebratic expression) a cubed is equal to 31
(Precalc) NEED HELP 100PTS: (−2 ≤ x ≤ 2) f(x) = csc(x)
A. Find the intervals on which the graph of y = f(x) is increasing and the intervals on which the graph of y = f(x) is decreasing. Answer in interval notation.
Increasing: ___
Decreasing: ___
B. Find all relative extrema, if any, of the graph of y = f(x).
Relative min: ___
Relative max: ___
Thank youu!! <333
Answer:
Step-by-step explanation:
y=csc(x) x∈ [-2,2]
[tex]A.\\\displaystyle\\Increasing: \ [-2,-\frac{\pi }{2})U(\frac{\pi }{2},2]\\\\Decreasing:\ (-\frac{\pi }{2},0)U(0,\frac{\pi }{2} ) \\\\B.\\\\Relative\ min:\ 1\\\\Relative \ max:\ -1[/tex]
Watching the graph:
Answer:
[tex]\textsf{Increasing}:\left[-2,-\dfrac{\pi}{2}\right) \textsf{ and }\left(\dfrac{\pi}{2},2\right][/tex]
[tex]\textsf{Decreasing}:\left(-\dfrac{\pi}{2}, 0\right) \textsf{ and }\left(0, \dfrac{\pi}{2}\right)[/tex]
[tex]\textsf{Relative min}: \left(\dfrac{\pi}{2},1 \right)[/tex]
[tex]\textsf{Relative max}: \left(-\dfrac{\pi}{2},-1 \right)[/tex]
Step-by-step explanation:
Part A
Given function:
[tex]f(x)=\csc (x), \quad -2\leq x\leq 2[/tex]
[tex]\csc(x)=\dfrac{1}{\sin(x)}[/tex]
Therefore, the function f(x) is undefined when sin(x) = 0, leading to vertical asymptotes at the value of x where sin(x) = 0.
[tex]\sin(x) = 0 \textsf{ at }x = 0\pm 2 \pi n, \pi \pm 2 \pi n[/tex]
Therefore, f(x) has a vertical asymptotes at x = -2π, -π, 0, π, 2π etc.
Where the graph of the sine function increases, the graph of the cosecant function decreases.
Where the graph of the sine function decreases, the graph of the cosecant function increases.
The sine function increases on the intervals:
[tex]\left(-\dfrac{\pi}{2}\pm 2 \pi n, \dfrac{\pi}{2}\pm 2 \pi n\right)[/tex]
and decreases on the intervals:
[tex]\left(\dfrac{\pi}{2}\pm 2 \pi n, \dfrac{3\pi}{2}\pm 2 \pi n\right)[/tex]
Therefore, for the interval -2 ≤ x ≤ 2, the cosecant function f(x):
Increases on the intervals:
[tex]\left[-2,-\dfrac{\pi}{2}\right) \textsf{ and }\left(\dfrac{\pi}{2},2\right][/tex]
Decreases on the intervals:
[tex]\left(-\dfrac{\pi}{2}, 0\right) \textsf{ and }\left(0, \dfrac{\pi}{2}\right)[/tex]
Part B
The relative minimums of the graph of the sine function are the relative maximums of the graph of the cosecant function.
The relative maximums of the graph of the sine function are the relative minimums of the graph of the cosecant function.
The sine function has a range of -1 ≤ sin(x) ≤ 1.
Therefore, its minimum points are when sin(x) = -1 and its maximum points are when sin(x) = 1.
[tex]\sin(x)=-1 \implies x=\dfrac{3\pi}{2}\pm 2 \pi n \implies \textsf{Minimum points}: \left(\dfrac{3\pi}{2}\pm 2 \pi n ,-1 \right)[/tex]
[tex]\sin(x)=1 \implies x=\dfrac{\pi}{2}\pm 2 \pi n \implies \textsf{Maximum points}: \left(\dfrac{\pi}{2}\pm 2 \pi n,1 \right)[/tex]
Therefore, the minimum and maximum points of the cosecant function in the given interval -2 ≤ x ≤ 2 are:
[tex]\textsf{Relative min}: \left(\dfrac{\pi}{2},1 \right)[/tex]
[tex]\textsf{Relative max}: \left(-\dfrac{\pi}{2},-1 \right)[/tex]
Note in the attached graph:
The given interval -2 ≤ x ≤ 2 is shown shaded in green.Vertical asymptotes are shown as red dashed lines.Function f(x) is the black curve.The sine function is the blue dashed curve.Relative min/max shown as black points.
Multiply:
-2x(3x - 4)
Enter the correct answer
Answer:
- 6x² + 8x
Step-by-step explanation:
- 2x(3x - 4) ← multiply each term in the parenthesis by - 2x
= - 6x² + 8x
Explain the difference between solving an equation with the variables all on one side compared to equations with variables on both sides.
An equation having variables on both sides can be solved by bringing all variables to one side.
An equation with all variables on one side can be solved by simply keeping the variables on the left and simplifying the value on the right. For example,
5x = 6 + 2x;
3x = 6;
x = 2.
For an equation with variables on both sides, just bring all variables on one side. After that, the same process like above is to be followed. For example,
5y - 3 - 3y = 3y + 5 - 3y;
5y - 3y - 3y + 3y = 5 + 3;
2y = 8;
y = 4;
Thus, methods for solving both kinds of equations is similar.
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An equation having variables on both sides can be solved by bringing all variables to one side.
An equation with all variables on one side can be solved by simply keeping the variables on the left and simplifying the value on the right. For example,
5x = 6 + 2x;
3x = 6;
x = 2.
For an equation with variables on both sides, just bring all variables on one side. After that, the same process like above is to be followed. For example,
5y - 3 - 3y = 3y + 5 - 3y;
5y - 3y - 3y + 3y = 5 + 3;
2y = 8;
y = 4;
Thus, methods for solving both kinds of equations is similar.
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Last year, Chau invested his money in two purchases. He purchased a certificate of deposit for 1000 that paid 2% interest per year and purchased 3000 in corporate bonds paying 7% interest per year.
The total interest earned at the end of first year is $250 and the percentage of interest for his total investment is 6.25%.
Given, Chau invested his money by purchasing the following:
a certificate of deposit for $1000 at the rate of 2% per year, and
corporate bonds for $3000 at the rate of 7% per year.
we know that simple interest is calculated by multiplying the amount invested P by the interest rate r times the number of years invested t.
therefore, I = P × r × t
a. The first investment has a principal of P = $1,000, r = 2% = 0.02, t = 1 yr
I₁ = 2000 × 0.04 × 1
I₁ = 40
The second investment has a principal P = $3,000, interest rate r = 7% = 0.07 and time t = 1yr
I₂ = 3000 × 0.07 × 1
I₂ = 210
Therefore, total interest = I₁ ₊ I₂
= 40 ₊ 210
= $250
b. The overall rate of interest can be found by dividing:
Total interest/Total amount invested × 100
= 250/(1000 ₊ 3000) × 100
= 250/4000 × 100
= 25/4
= 6.25%
Hence we get the total interest earned at the end of first year as $250 and its overall rate of interest as 6.25%
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Your question was incomplete. Please find the missing content here.
Last year, Chau invested his money in two purchases. He purchased a certificate of deposit for $1000 that paid 2% interest per year and purchased $3000 in corporate bonds paying 7% interest per year.
(a) What was the total investment earned at the end of 1 year?
(b) What was the percentage interest for her total investment?
area of a parallelogram find the areas of the parallelograms whose vertices are given in exercises 35–40.
The area of parallelogram ABCD is found to be 2√3 square units.
What is parallelogram?A quadrilateral is known as a parallelogram in geometry. The opposite sides of a parallelogram are parallel & equal in length. Rhombus, rectangle, & square are a few examples of parallelograms.
We know that diagonal of such a parallelogram divides it into two equal triangles.
So, parallelogram area,
ABCD = 2× area of ΔABC (equation 1)
The area pf the triangle is found through the vertices are (x₁,y₁), (x₂,y₂), (x₃,y₃) is;
Area = (1/2)×[x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)]
The vertices of the triangles are given as;
A(2,4), B(2+ √3 ,5) and C(2,6)
Area = (1/2)×[2(5−6) + (2+√3)(6−4) + 2(4−5)]
Area = (1/2)×[−2+2(2+ √3)−2]
Area = √3
When we plug this value into equation (1),
Parallelogram area,
ABCD = 2×the area of ABC
ABCD = 2×√3
ABCD = 2√3
Thus, the area of the parallelogram ABCD id estimated as 2√3 square units.
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The correct question is -
Find the area of a parallelogram ABCD if three of its vertices are A(2,4), B(2+ √3 ,5) and C(2,6)
v/9 - 7 = -8
I'll give brainliest!! please explain
By isolating the variable, we will see that the solution of the linear equation is v = -9
How to solve the linear equation?Here we have the following linear equation:
v/9 - 7 = -8
Where we can see that the variable is v. To solve this, we need to perform operations in both sides of the linear equation in a way such that the variable is isolated in one of the sides.
Adding 7 in both sides we get:
v/9 - 7 + 7 = -8 + 7
v/9 = -1
Now we multiply both sides by 9:
(v/9)*9 = -1*9 = -9
v = -9
We conclude that the solution of the linear equation is v = -9.
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Help pleaseeeeeeeeee
Answer:
y2 = m*(x2 - x1) + y1
Step-by-step explanation:
m = (y2 - y1) / (x2 - x1)
y2 - y1 = m*(x2 - x1)
y2 = m*(x2 - x1) + y1
write the non-teerminating decimal as fraction 0.555555555...
Answer:
111111111/200000000
please help me, i have a test soon :/
Answer:
-2 <= y <= 4
Step-by-step explanation:
-3 <= 2y + 1 <= 9
-4 <= 2y <= 8
-2 <= y <= 4
Answer:
-2 <= y <= 4
Step-by-step explanation:
-3 <= 2y + 1 <= 9
-4 <= 2y <= 8
-2 <= y <= 4
