what's the most specific subset of real numbers that the following number belongs in? 8.34
1. rational
2. integer
3. whole
4. irrational

Answer:

Not sure, is there a problem or only the rant? lol. I'd appreciate my first brainliest though.

Step-by-step explanation:

Answer: 1.5 Burgers an hour

1/8 x 12 = 1.5

Multiply 1/8 by 12 to get and hour because 12/12ths = 1 hour

The direction of the net magnetic field is [tex]$167.36^{\circ}$[/tex]

[tex]q_1=-4 \mathrm{nC} \text { at }(0.6,0.8)[/tex]

[tex]$q_2=6 \mathrm{nC}$[/tex] at (0.6,0)

[tex]$r_1=$[/tex]Distance of [tex]$q_1$[/tex] from origin[tex]$=\sqrt{0.6^2+0.8^2}$[/tex]

[tex]$r_2=$[/tex] Distance of [tex]$q_2$[/tex] from origin [tex]$=0.6$[/tex]

[tex]$\mathrm{k}=$[/tex] Coulomb constant[tex]$=9[/tex]times [tex]10^9 \mathrm{Nm}^2 / \mathrm{C}^2$[/tex]

Electric field is given by

[tex]&E_1=\frac{k q_1}{r_1^2} \\[/tex]

[tex]&\Rightarrow E_1=\frac{9 \times 10^9 \times 4 \times 10^{-9}}{\sqrt{0.6^2+0.8^2}} \\[/tex]

[tex]&\Rightarrow E_1=36 \mathrm{~N} / \mathrm{C}[/tex]

[tex]&\theta=\tan ^{-1} \frac{0.8}{0.6} \\[/tex]

[tex]&\Rightarrow \theta=53.13^{\circ} \\[/tex]

[tex]&E_1=36 \cos 53.13^{\circ} \hat{i}+36 \sin 53.13^{\circ} \hat{j} \\[/tex]

[tex]&\Rightarrow E_1=21.6 \hat{i}+28.8 \hat{j}[/tex]

[tex]&E_2=\frac{k q_2}{r_2^2} \\[/tex]

[tex]&\Rightarrow E_2=\frac{9 \times 10^9 \times 6 \times 10^{-9}}{0.6^2} \\[/tex]

[tex]&\Rightarrow E_2=150 \mathrm{~N} / \mathrm{C}[/tex]

The charge [tex]$q_2$[/tex] is on the [tex]$\mathrm{x}$[/tex] axis itself and it is pointing towards the origin (left side) so the sign will be negative

[tex]E_2=-150 \hat{i}[/tex]

Resultant electric field

[tex]&E=E_1+E_2 \\[/tex]

[tex]&\Rightarrow E=21.6 \hat{i}+28.8 \hat{j}+(-150 \hat{i}) \\[/tex]

[tex]&\Rightarrow E=-128.4 \hat{i}+28.8 \hat{j}[/tex]

Magnitude of electric field is given by

[tex]&|E|=\sqrt{(-128.4)^2+28.8^2} \\[/tex]

[tex]&\Rightarrow|E|=121.6 \mathrm{~N} / \mathrm{C}[/tex]

Magnitude of the net electric field is [tex]$121.6 \mathrm{~N} / \mathrm{C}$[/tex]

Direction is given by

[tex]\theta=\tan ^{-1} \frac{128.4}{28.8}=77.36^{\circ}[/tex]

From the -x axis

[tex](90+77.36)^{\circ}=167.36^{\circ}[/tex]

The direction of the net magnetic field is [tex]$167.36^{\circ}$[/tex]

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Answer:

its true

Step-by-step explanation:

Answer:

121 x 3 = 363
117 + 108 = 225

363 - 225 = 138

138 is the third game
I'm not very sure how to write an equation for this, I guess it would look something like
117 + 108 + x = 363

Step-by-step explanation:

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

Answer:

9

Step-by-step explanation:

So there's 3 1's, 2 2's, 2 3's, 1 4, 2 5's, a 6, a 7, an 8, 2 0's, and no 9's.  

money would she have at the end of vacation = 377,789,318,629,571,617,095.67 dollars.

When interest is applied to a principal amount together with the interest that has already been paid, this process is known as compounding. This means that compounding, sometimes known as the "wonder of compounding," can be thought of as interest on the compound, which has the effect of increasing returns from interest over time.

Current good compounding practices refer to the minimal requirements for the procedures, facilities, and controls used to compound medicine to ensure that it has the identity, and strength, and satisfies the quality and purity requirements it is claimed to have.

She puts in one penny the first day, 2 pennies the second, 4 pennies the third...and so on.

The total sum is thus,

(1, 3, 7, 15, 31, 63, 127)

Which translate to

(2^1-1, 2^2-1, 2^3-1, 2^4-1, 2^5-1, 2^6-1, 2^7-1,..)

So at the end of the 75th day, the total amount is 2^75-1

or

37778931862957161709567 pennies

or

377,789,318,629,571,617,095.67 dollars.

money would she have at the end of vacation =  377,789,318,629,571,617,095.67 dollars.

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I understand that the question you are looking for is:

Your friend is saving pennies. She puts one penny into her piggy bank the first day, two pennies the second day, four the third day, and so on, doubling the number of pennies added. How many much money would she have at the end of vacation, if she could keep saving at this rate? Vacation lasts 75 days.

Answer:

Step-by-step explanation:

Given three relations between the costs of balls, bats, and bases, you want to find the cost of each.

Solving three linear equations in three unknowns can be accomplished easily by any number of calculators, apps, or spreadsheets. Here, we'll use an ad hoc solution.

Subtracting twice the third equation from the second, we have ...

  (4 balls + 8 bats + 2 bases) -(2(2 balls + 3 bats + 1 base) = 78 -2(33.60)

  2 bats = 10.80 . . . . . . . simplify

  1 bat = 5.40 . . . . . . divide by 2

Subtracting the second equation from the first, we have ...

  (10 balls +3 bats +2 bases) -(4 balls +8 bats +2 bases) = (99) -(78)

  6 balls -5 bats = 21 . . . . . simplify

  6 balls = 21 + 5(5.40) . . . . . add 5 bats and substitute their cost

  6 balls = 48 . . . . . . . . simplify

  1 ball = 8.00 . . . . . . . divide by 6

Using the last equation, we can find the cost of 1 base.

  1 base = 33.60 -2 balls -3 bats = 33.60 -2(8.00) -3(5.40)

  1 base = 1.40

The costs are ...

  1 ball: $8.00

  1 bat: $5.40

  1 base: $1.40

Answer: 68

Step-by-step explanation: do 75+37 which equals 112 then subtract 180 by 112 which equals 68

hope this helps

Answer:

A

Step-by-step explanation:

the sum of the 3 angles in a triangle = 180° , then

x + 37° + 75° = 180° , that is

x + 112° = 180° ( subtract 112° from both sides )

x = 68°

Answer:Sounds delicious

Step-by-step explanation:

Sounds nice, ill make this

Answer:

Domain:

$%error%$

Range:

$%error%$

Explanation:

Both

x

and

y

belong to all the real numbers since there is no restriction on either the domain or the range.

Step-by-step explanation:

The weighted average is -5

The formula for the weighted average is

                                        = Σwixi/Σwi               (1)

                                             Where wi = are the weights and

                                                         xi are the coordinates

We have been given that

w1 = 3   ,  x1 = -8            and  w2 = 1  , x2 = 4

Σwixi = w1x1 + w2x2

         = 3*-8  + 1*4

         = -24 + 4

        = -20

Σwi = w1 + w2

       = 3 + 1

      = 4

Now putting the required value in equation (1) we get

Weighted average = -20/4

                                 = -5

Hence the weighted average is -5

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(a) The third term of the sequence is 19.

(b) The term-to-term rule of the new sequence is "subtract 13 and then divide by 6".

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Answer:

320

Step-by-step explanation:

Plug the 4 into x and go from left to right:

4 times 4 is 16 times 20 is 320

Answer:

7

Step-by-step explanation:

22=6x+1-3x

21=6x-3x

21=3x

7=x

Answer:

-96/7x or 13.714x

Step-by-step explanation:

-4/7+ 2/7x - 14x+4/7

first we do

4/7-4/7 which is zero, so we can cancel those out.

then we do

2/7x-14x ( or you can do -14x+2/7, it’s the same thing

use your calculator to make this easier. if you look you’ll be able to find a fraction button on most

after we do 2/7x-14x , we get -96/7x

if you want it in a fraction just divide and you’ll get -13.714x

Magnitude of the resultant vector = 31.3 lb and  Angle of the resultant vector = 23.3o are  the magnitude of the resultant force and the angle .

what is magnitude of forces?

a = 26 lb

Angle made by the vector 'a' = θ1 = 45o

Component of vector 'a' in the X-direction = ax = aCosθ1 = (26)Cos(45) = 18.38 lb

Component of vector 'a' in the Y-direction = ay = aSinθ1 = (26)Sin(45) = 18.38 lb

b = 12 lb

Angle made by the vector 'b' = θ2 = 30o

Component of vector 'b' in the X-direction = bx = bCosθ2 = (12)Cos(30) = 10.39 lb

Component of vector 'b' in the Y-direction = by = -bSinθ2 = -(12)Sin(30) = -6 lb

Let the resultant vector be 'c'

Component of vector 'c' in the X-direction = cx

cx = ax + bx

cx = 18.38 + 10.39

cx = 28.77 lb

Component of vector 'c' in the Y-direction = cy

cy = ay + by

cy = 18.38 + (-6)

cy = 12.38 lb

c=104)2 + (cy)

c= (28.77)2 + (12.38)2

c = 31.3 lb

Angle made by vector 'c' = θ

Tanθ =

Tanθ = 12.38 28.77

θ = 23.3o

a) Magnitude of the resultant vector = 31.3 lb

b) Angle of the resultant vector = 23.3o

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THE COMPLETE QUESTION IS  -

Find the magnitude of the resultant force and the angle it makes with the positive x-axis. (Let a = 26 lb and b = 12 lb. Round your answers to one decimal place.)

Answer:

x = 17/5

Step-by-step explanation:

5x + 3 = 20

5x + 3-3 = 20 - 3

5x = 17

divide both by 5

Answer:

Your answer is 65

Step-by-step explanation:

f(x) = x² - 4x - 12

f(-7) = (-7)² - 4 x (-7) - 12

= 49 - (-28) - 12

= 49 + 28 - 12

= 77 - 12

= 65

The amount of money the women had in the beggining was $75.

Let the total amout of money the women had intially be x.

According to the questio.

A woman went shopping and spent 2/3 of all the money she had. Then she lost 3/5 of what she had left after shopping.

So, the amount of money she spent for shopping = (2/3)x = 2x/3

⇒ The amount of money she had after shopping

= x -2x/3

= 3x -2x/3

= x/3

Now, the amount of money she lost 3/5 × (x/3) = x/5

⇒ Amount of money she have after the lost of money

= x/3  - x/5

= 5x - 3x /15

= 2x/15

It is given that she have $10.

⇒ 2x/15 = 10

⇒ 2x = 150

⇒ x = 150/2

⇒ x = $75

Hence, the amount of money the women had in the beggining was $75.

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The expressions that are equal to a rational number are [(2/3)+(4/5)], [(√3) - (√3)], and [(√49)(√1)].

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Answer:

The third option is right

Step-by-step explanation:

This is because if you have two negative it becomes a positive

1, 3, 4,5

The polynomial equations of degree two in one variable of type f(x) = ax² + bx + c = 0 and with a, b, c, and R R and a 0 are known as quadratic equations. It is a quadratic equation in its general form, where "a" stands for the leading coefficient and "c" for the absolute term of f. (x). The roots of the quadratic equation are the values of x that fulfill the equation (α, β).

It is a given that the quadratic equation has two roots. Roots might have either a real or imaginary nature.

1)m( 2m + 3) =0

2m²+3m=0

Yes it is a quadratic equation.

2) 11t² (t - 4 ) = 0

11t³-44t²=0

NO

3) 5h + h² = - 7

Yes it is a quadratic equation.

4)4b (b - 2 ) = - 8

4b²-8b +8 =0

Yes, it is a quadratic equation.

5) y² + 7y - 6 = 0

Yes it is a quadratic equation.

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The value of complex number 6 + 7i / 6-7i is -13 / 85 + 84i/85

Complex numbers are those that are represented as a+ib, where a and b are actual numbers and I is a fictitious number termed a "iota." I has the value (-1). As an illustration, the complex number 2+3i is made up of the real number 2 (Re) and the imaginary number 3i (Im).

Given the complex number is -

6 + 7i / 6-7i

⇒ 6 + 7i / 6 - 7i × 6 + 7i / 6 + 7i

⇒ (6+7i)² / 6² - 7²(i²)

Using (a+b)² = a² + b² + 2ab    

⇒ 6² + (7i)² +2(6)(7i) / 36 - 49(-1)

⇒ 36 - 49 + 84i / 36 + 49

⇒ -13 + 84i / 85

⇒ -13 / 85 + 84i/85

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Answer:

[tex](3x-3y-4)(x-y-2)[/tex]

Step-by-step explanation:

Given expression:

[tex]3(x-y)^2-10(x-y)+8[/tex]

Let u = (x - y):

[tex]\implies 3u^2-10u+8[/tex]

To factor a quadratic in the form  [tex]ax^2+bx+c[/tex]  find two numbers that multiply to [tex]ac[/tex] and sum to [tex]b[/tex]:

[tex]\implies ac=3 \cdot 8=24[/tex]

[tex]\implies b=-10[/tex]

Therefore, the numbers are: -6 and -4.

Rewrite [tex]b[/tex] as the sum of these two numbers:

[tex]\implies 3u^2-6u-4u+8[/tex]

Factor the first two terms and the last two terms separately:

[tex]\implies 3u(u-2)-4(u-2)[/tex]

Factor out the common term (u - 2):

[tex]\implies (3u-4)(u-2)[/tex]

Substitute back in u = (x - y):

[tex]\implies (3(x-y)-4)((x-y)-2)[/tex]

Simplify:

[tex]\implies (3x-3y-4)(x-y-2)[/tex]

Answer:

25n

Step-by-step explanation:

product of n and 25

Product means multiply

25n

Answer:

88 [tex]cm^{2}[/tex]

Step-by-step explanation:

We need to find the area of the rectangle and the triangle.

Area of the rectangle:

a = length x width

a = 11 x 6 = 66

Area of the triangle:

a = [tex]\frac{ b x h}{2}[/tex]  We need to find the base and height of the triangle.  The base is the same length as the length of the rectangle: 11 and the height is 10 - 6 or 4

a = [tex]\frac{11 x 4}{2}[/tex]

a = [tex]\frac{44}{2}[/tex]

a = 22

Add the area of the rectangle and the triangle together.  66 + 22 = 88

If [tex]y=x^m[/tex] is a solution to the ODE

[tex]x^2 y'' - 7xy' + 15y = 0[/tex]

then substituting [tex]y[/tex] and its derivatives

[tex]y' = mx^{m-1} \text{ and } y'' = m(m-1)x^{m-2}[/tex]

gives

[tex]m(m-1)x^2x^{m-2} - 7mxx^{m-1} + 15x^m = 0[/tex]

[tex]m(m-1)x^{m} - 7mx^{m} + 15x^m = 0[/tex]

[tex](m(m-1) - 7m + 15)x^{m} = 0[/tex]

We ignore the trivial case of [tex]y=x^m=0[/tex]. Solve for [tex]m[/tex].

[tex]m(m-1) - 7m + 15 = 0[/tex]

[tex]m^2 - 8m + 15 = 0[/tex]

[tex](m - 3) (m - 5) = 0[/tex]

[tex]\implies \boxed{m=3} \text{ or } \boxed{m=5}[/tex]