Triangle PQR is transformed to triangle P′Q′R′. Triangle PQR has vertices P(3, −6), Q(0, 9), and R(−3, 0). Triangle P′Q′R′ has vertices P′(1, −2), Q′(0, 3), and R′(−1, 0).

Plot triangles PQR and P′Q′R′ on your own coordinate grid.

Part A: What is the scale factor of the dilation that transforms triangle PQR to triangle P′Q′R′? Explain your answer. (4 points)

Part B: Write the coordinates of triangle P′′Q′′R′′ obtained after P′Q′R′ is reflected about the y-axis. (4 points)

Part C: Are the two triangles PQR and P′'Q′'R′' congruent? Explain your answer. (2 points)

Answer:

If what youre asking is √162, then the answer is 9√2

Step-by-step explanation:

Answer: 12.73

type it in your calculator if you can

The wind instrument with the closed end.

Why is it known as a node?

Node is the actual name in use. It was initially intended to be used as a web application, but the author changed the name to node after realizing it could be applied to a variety of situations.

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If we have the x and y components of a vector, the trigonometry function that can be used to determine its angle relative to the x-axis is cosine function.

For given question,

Let α be an angle between vector a and vector b.

The angles between two vectors is given by,

cos(α) = [tex]\frac{\vec a . \vec b}{|\vec a | | \vec b|}[/tex]

The x component of vector is usually denoted by [tex]\vec i[/tex]

Let vector be [tex]x\vec i + y\vec j[/tex]

Let [tex]\vec a=\vec i, ~ \vec b=x\vec i + y\vec j[/tex]

[tex]\vec a . \vec b=x[/tex]

[tex]|\vec a|=1[/tex]

[tex]|\vec b|=\sqrt{x^2+y^2}[/tex]

So, the angle between the vector and x-axis is [tex]cos^{-1}(\frac{x}{\sqrt{x^2+y^2} } )[/tex]

Therefore, if we have the x and y components of a vector, the trigonometry function that can be used to determine its angle relative to the x-axis is cosine function.

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Answer: Taxi driver has at most $10 to spend on the cab ride, he can travel at most 12.7 miles.

Step-by-step explanation:

A Taxi driver charges a flat rate = 7.25 dollars

taxi fare for 1 mile = 0.65 dollars

Suppose we consider Total money taxi driver can spend = 10 dollars

Let taxi driver travel x miles

Total charges = flat rate charge + taxi fare for each mile(distance) travelled

Find the value y = [?] + [?]x

suppose these two question marks indicate z1,z2

replace with y=10 and z1=1.75 and z2=0.65 values

Then y = [z1] + [z2]x

10 = 1.75 + 0.65(x)

0.65(x) = 10 - 1.75

0.65(x)= 8.25

x = 8.25/0.65

x = 12.7 miles

If Taxi driver has at most $10 to spend on the cab ride, he can travel at most 12.7 miles.

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Answer:

16

Step-by-step explanation:

[tex]16^{2} =256[/tex]

_____________________

Solution:

Exact Form:

[tex]\frac{4}{7}-(-\frac{3}{8}) = \frac{53}{56}[/tex]

______________________

(^Note^)

To subtract fractions, find the LCD (Least Common Denominator), then combine.

Hope this helps! If so, please lmk! Thanks and good luck!

Answer: 53/56

Step-by-step explanation:

sorry if im wrong but since there is 2 negative signs it is going to become positive. so..

4/7+3/8

then make the denominators the same (56)

then multiply the numerators by the number you multiplied for the denominator for the question.

answer: 32/56+21/56 = 53/56

Answer:

4000inches

Step-by-step explanation:

1000*4 = 4000inches

Answer: 4,000 inches

Step-by-step explanation:

this is because 4 times 1000 is 4000 so the Hyperion tree would be 4000 inches tall

Answer:
x^4−3x^3+5

Step-by-step explanation:

Simplify the answer and convert it to standard form.

Answer: ANSWER

The simplified polynomial in standard form is

EXPLANATION

The given expression is

We group the terms with the same exponents,

We simplify to obtain,

Since the expression is a polynomial, writing it in standard form means writing the simplified form in descending powers of x.

Step-by-step explanation: gl

Answer:

Week 1 =11

Week 2 = 9

Week 3 = 7

Week 4 = 5

Week = 3

11 + 9 + 7 + 5 + 3 = 35

Pattern: She is losing 2 less pounds each week. There is a pattern.

Answer:

=45867

Step-by-step explanation:

[tex]\frac{\begin{matrix}\:\:&\textbf{\:\:}&7&9&9&13\\ \:\:&\textbf{7}&\linethrough{8}&\linethrough{10}&\linethrough{10}&\linethrough{3}\\ -&\textbf{3}&2&1&3&6\end{matrix}}{\begin{matrix}\:\:&\textbf{4}&5&8&6&7\end{matrix}}[/tex]

The given bounded region is the set

[tex]R = \left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^4 \le y \le x^{1/4} \right\}[/tex]

assuming the curves are [tex]y=x^4[/tex] and [tex]x=y^4\implies y=x^{1/4}[/tex] (since [tex]x>0[/tex] in the first quadrant).

The coordinates of the centroid are [tex](\bar x, \bar y)[/tex] where [tex]\bar x[/tex] and [tex]\bar y[/tex] are the average values of [tex]x[/tex] and [tex]y[/tex], respectively, over the region [tex]R[/tex]. These are given by the ratios

[tex]\bar x = \dfrac{\displaystyle \iint_R x \, dA}{\displaystyle \iint_R dA} \text{ and } \bar y = \dfrac{\displaystyle \iint_R y\,dA}{\displaystyle \iint_R dA}[/tex]

Compute the area of [tex]R[/tex].

[tex]\displaystyle \iint_R dA = \int_0^1 \int_{x^4}^{x^{1/4}} dy \, dx \\\\ ~~~~~~~~ = \int_0^1 \left(x^{1/4} - x^4\right) \, dx \\\\ ~~~~~~~~ = \frac45 - \frac15 = \frac35[/tex]

Integrate [tex]x[/tex] and [tex]y[/tex] over [tex]R[/tex].

[tex]\displaystyle \iint_R x \, dA = \int_0^1 \int_{x^4}^{x^{1/4}} x \, dy \, dx \\\\ ~~~~~~~~ = \int_0^1 x \left(x^{1/4} - x^4\right) \, dx \\\\ ~~~~~~~~ = \int_0^1 \left(x^{5/4} - x^5\right) \, dx \\\\ ~~~~~~~~ = \frac49 - \frac16 = \frac5{18}[/tex]

[tex]\displaystyle \iint_R y \, dA = \int_0^1 \int_{x^4}^{x^{1/4}} y \, dy \, dx \\\\ ~~~~~~~~ = \frac12 \int_0^1 \left((x^{1/4})^2 - (x^4)^2\right) \, dx \\\\ ~~~~~~~~ = \frac12 \int_0^1 \left(x^{1/2} - x^8\right) \, dx \\\\ ~~~~~~~~ = \frac12 \left(\frac23 - \frac19\right) = \frac5{18}[/tex]

Then the centroid's coordinates are

[tex]\bar x = \dfrac{\frac5{18}}{\frac35} = \boxed{\frac{25}{54}} \approx 0.463[/tex]

[tex]\bar y = \dfrac{\frac5{18}}{\frac35} = \boxed{\frac{25}{54}}[/tex]

Answer:

It would be 3710.

Step-by-step explanation:

Answer:

310 hamburgers were sold on Saturday

Step-by-step explanation:

1x + 70 =380

    -70   -70     Reverse

1x   =  310

/1         /1          Divide

x =310

Linear equations are equations that has a leading degree of 1. The value of x that makes the equation true is 1/4

Linear equation are equations that has a linear degree of 1. The standard linear equation is y = mx + b

Given the expression below

2(3 - 7x) = 4 - 6x

Expand

6 - 14x = 4 - 6x

Collect the like terms

6 - 14x = 4 - 6x

-14x + 6x = 4 -6

-8x = -2

Divide both sides by -8

-8x/-8 = -2/-8

x = 1/4

Hence the value of x that makes the equation true is 1/4

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Answer: 401

Step-by-step explanation:

-177 + 578 = 401

Answer:

1/2

Step-by-step explanation:

0.5 is half of 1 so 1/2 is 0.5 as a fraction

Answer:

Step-by-step explanation:

it provides services to both the user and the programs.

it provides program an environment to execute.

Answer:

17716.09385 is sum of multiplication .

What does multiply mean?

= 2.53 x 1019 + 3.197 x 1017 + 2.56197 x 1019 + 3.2223 x 1019 + 2.56197 x 1036 + 3.2223 x 1036

= 2578.07 + 3251.349 + 2610.64743 + 3283.5237 + 2654.20092 + 3338.3028

= 17716.09385

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Answer:

180

Step-by-step explanation:

Because its true

Answer:

well it would be [tex]-\frac{1}{3}[/tex]

Step-by-step explanation:

Simply put [tex]-\frac{3}{9}[/tex]. The top and bottom are divisible by 3 so you simplify and you end up with negative one third.

Answer: 144N

Step-by-step explanation:

A=acceleration. N=net force. M=mass

A=N/M

4.5=N/32

4.5*32=N

N=144N

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Net Force acting on a body can be determined by formula :

[tex]\qquad \sf  \dashrightarrow \: f = m \times a[/tex]

where,

[tex]\qquad \sf  \dashrightarrow \: f = 32 \times 4.5[/tex]

[tex]\qquad \sf  \dashrightarrow \: f = 144 \: \: N[/tex]

So, the net force acting on the body is 144 Newtons.

      Of all of the common assumptions that we discussed in class, I think one of the most common is the idea that a children’s text should in some way teach the reader something.  We of course talked about the term didactic, and how a didactic book strongly pushes a lesson onto the reader, telling them that they should believe this or that.  Many times a reason for that lesson isn’t even given, as though the young person reading the book should just accept that lesson because they are told to, because the other knows better.  As I was reading Cat in the Hat by Dr. Seuss, the book I selected for the assignment, I was hoping that it wouldn’t be as didactic as most other children’s books, and that it would be as playful and exciting as I remember as a child.  On the last two pages of the book, however, the absent mother returns home, the cat has disappeared, the children are behaving nicely, sitting in chairs, and it is pretty obvious that even though they got into mischief they are still good children after all.  Nothing really has changed at the end of the book.  Although all sorts of things got played with, and the children broke the rules I am sure they know about (like, “Don’t fly kites in the house”), major boundaries were never crossed.

           We talked about how the opposite of a didactic book might be an ambiguous book, or a book that encourages the reader to think about issues, to make decisions for themselves.  In that kind of book, the author usually wants to the reader to think for her or himself, to understand that some things are difficult, even for adults.  The author may present a problem and ask you what you think, or might just never come around to saying exactly what you are supposed to believe.  The last page of Cat in the Hat ends with the narrator saying, referring to the mother, “Should we tell her about it? / Now what SHOULD we do? / Well . . . / What would YOU do / If your mother asked you?” (61).  In some ways, this is probably a pretty ambiguous ending.  The author asks the reader that if your mother left, if someone wanted you to do what you weren’t supposed to, if you did it anyway, and if you didn’t get caught, then would you tell your mother or father what happened?  Most adults wouldn’t tell what happened themselves, but the question is there anyway, and it seems to be really asking children what they believe.

           But it doesn’t seem really that ambiguous.  If the book were really ambiguous it would be breaking the Typical Case Prototype of children’s books, and in almost every other way the book keeps to those prototypes.  As Nodelman describes it, children’s books are typically bright, colorful, funny, entertaining, and maybe sometimes rhyming.  Children’s books portray children as the way adults typically think of them, as crazy kids who aren’t serious like adults, or innocent angels who would never really do any harm when they play.  Dr. Suess portrays typical kids, bored by the rain, wanting to do something wild.  Although Seuss’s style is strange, the children even look like the sort of standard white children that appear in most books, the girl in a dress and ribbon in her hair.  We saw in class how these children are a lot like the standard one’s in Cassie’s history textbook  And although strange things happen in the book – a talking cat, a couple of strange Things, a lot of things getting thrown around – it is the kind of play we come to expect in children’s lives, especially in the sorts of standard things shown on television and in movies.

           In fact, the children never quite seem to trust the Cat, and they always just sort of watch him play.  The children never really do anything that crazy themselves.  The Fish, who sounds a lot like an adult, is always there to warn them, and in the end everything gets cleaned up.  Of course the book is fun and playful, and is obviously one of the most famous and liked picture books ever made, but it is still pretty straightforward.  Cat in the Hat reinforces and demonstrates almost all of the typical assumptions about childhood, and it fulfills all of the typical case prototypes of children’s books.  Examining it made me think about how the book might have changed in recent years, especially since children are rarely bored when they are at home any more (with all of the stuff they own to play with).  But more than that, it made me think about why we expect all children’s books to be like this, why it is always considered one of the best books for children.  Although I like typical children’s books, it makes me also interested in books that don’t do what we expect.  The book was written 1957, and in so many ways children’s books have become so incredibly different since then.  But in a lot of other ways, some good, some bad, they haven’t changed at all.    

Answer:

distributive property

subtraction

division property of equality

Answer: 4.631*10^5

Step-by-step explanation:

463,100=

400,000+63,100=

4*100,000+(63,100/100,000)*100,000=

4*10^5+(631/1000)*10^5=

4*10^5+0.631*10^5=

(4+0.631)*10^5=4.631*10^5

The largest area of rectangle can be A= (11√11)/√2

To find the area of a rectangle, we multiply the length of the rectangle by the width of the rectangle.

Area = l × w. l = length. w = width.

Given:

y=11-x²

Consider,

x is the length of the base

y is the vertices on the curve (width)

As, the area of a rectangle with its base on the x-axis.

So, base =2x

Then Area of rectangle

A = 2x(11-x²)

Foe maximum area, dA/dx=0

dA/dx = 22-4x²

22-4x² =0

22=4x²

11/2 = x²

x=√(11/2)

Now, Put x=√(11/2) in area

A= 2*√(11/2) ( 11-11/2)

A= √22(11/2)

A= (11√11)/√2

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Answer:

(E) 6x+12

relations: A relation R is the subset of the cartesian product of X x Y, where X and Y are two non-empty elements. It is derived by stating the relationship between the first element and second element of the ordered pair of X × Y. The set of all primary elements of the ordered pairs is called a domain of R and the set of all second elements of the ordered pairs is called a range of R.

functions: A relation ‘f’ is said to be a function, if every element of a non-empty set X, has only one image or range to a non-empty set Y.

f(x) = 3x + 4

2 * f(x) + 4 = (2 × f(x)) + 4

From above equation

= (2 × (3x + 4)) + 4

= (2 × 3x) + (2 × 4) + 4

= 6x + 8 + 4

= 6x + 12

Therefore, the value of 2f(x) + 4 is ′6x + 12′.

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Answer:

[tex]\frac{-8}{27}[/tex]

Step-by-step explanation:

[tex]\frac{-5}{9}[/tex] - [tex]\frac{-7}{27}[/tex]  Subtracting a negative is the same as adding a positive.  So I would change the form to addition.

[tex]\frac{-5}{9}[/tex] + [tex]\frac{7}{27}[/tex]  Now to add, we need a common denominator.  Let's us 27

[tex]\frac{-5}{9}[/tex] = [tex]\frac{-15}{27}[/tex]  We multiple the numerator and denominator (top and bottom) by 3 to make an equivalent fraction.

[tex]\frac{-15}{27}[/tex] + [tex]\frac{7}{27}[/tex]  the bottom number stays the same and we add the top numbers

-15 + 7 = -8

[tex]\frac{-8}{27}[/tex]

Answer: -8/27

Step-by-step explanation:

[tex]\displaystyle\\-\frac{5}{9} -(-\frac{7}{27} )=\\\\-\frac{5*3}{9*3} +\frac{7}{27} =\\\\\frac{-15}{27}+\frac{7}{27}=\\\\ \frac{-15+7}{27}=\\\\ \frac{-8}{27} =\\\\-\frac{8}{27}[/tex]

The six trigonometric functions of theta for the point (-4, -4) is

sin Θ = -1/√2

cos Θ = -1/√2

tan Θ = 1

cosec Θ = -√2

sec Θ = -√2

cot Θ = 1

Trigonometric Functions:

Trigonometric functions are defined as the functions of an angle of a triangle. It means that the relationship between the angles and sides of a triangle.

The six trigonometric functions are,

Sin Θ =Opposite/Hypotenuse

Cos Θ = Adjacent/Hypotenuse

Tan Θ = Opposite/Adjacent

Sec Θ =  Hypotenuse/Adjacent

Cosec Θ  = Hypotenuse/Opposite

cot Θ  = Adjacent/Opposite

Given,

Let (-4,-4) be a point on the terminal side of theta in standard position.

Here we need to find the exact values of six trigonometric functions.

Here the give point (-4,-4) represents the values of (opposite, adjacent).

So, the opposite = -4

and adjacent = -4

Now we have to find the hypotenuse of the point,

For that, we have to use the Pythagoras theorem,

hypotenuse = √oppostie² + adjacent²

Therefore,

=> hypotenuse = √(-4)² + (-4)²

=> hypotenuse = √16 + 16

=> hypotenuse = √32

it can be written as,

=> hypotenuse = √2 x 16

=> hypotenuse = 4√2

Now the six trigonometric functions are based on the formula,

sin Θ = -4/4√2 => sin Θ = -1/√2

cos Θ = -4/4√2 => cos Θ = -1/√2

tan Θ = -4/-4 => tan Θ = 1

cosec Θ = 4√2/-4 => cosec Θ  = -√2

sec Θ = 4√2/-4 =>  sec Θ  = -√2

cot Θ = -4/-4 => cot Θ = 1

So, all the six trigonometric values are identified.

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Answer: 166

We’ll give it your best mate keep it up