This pie chart shows several ways that the United States made electricity in 2009. The chart shows that

The correct answer for the The last quarter phase of the moon is it crosses the meridian at sunrise .

A third quarter moon, or last quarter moon, rises around midnight and sets around noon. The Moon is nearly back to the point in its orbit where its dayside faces the Sun directly, and all we see from our vantage point is a thin curve.

The Last or Third Quarter is when we can see half of the Moon's illuminated portion and half of its shadow portion. This is why this phase is commonly referred to as Half Moon. We can only see half of the Moon because it is at a 90-degree angle to the Earth and Sun.

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According to the given statement the height of the object thrown is =20.1m

Initial condition, or initial speed, refers to an object's speed at the start of a measurement. The average speed is the average of the initial and final speeds, or the ratio of the distance travelled to the time required. The speed difference between the initial and final speeds is the change in speed.

Start by dividing the acceleration by the time to determine the beginning velocity. Then, divide that number by 2 and write down the quotient you got. Next, divide the distance by the time and write down that quotient as well. To obtain the beginning velocity, finally remove your first quotient from your second quotient.

The right answer is s= 20.1m

s= -8t+0.5gt^2

t=3

s=20.1 m

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The appropriate word in the blank is → Line.

We have a statement regarding Voltage controls.

We have to fill in the blank with appropriate word.

Voltage control is necessary to prevent damage such as overheating of generators and motors, to reduce transmission losses.

According to the question, we have -

____ voltage controls are simply controls that do not employ the use of a control transformer to change the voltage to a lower value.

The appropriate word for the blank is → Line. Line voltage controls do not employ control transformer to decrease voltage. Line voltage controllers are designed to regulate the voltage of HVAC systems which require direct electrical power. These controllers are also known as inline thermostats and are typically connected to wires supplying 120 to 240 volts of power to heating or cooling device.

Hence, the appropriate word for the blank is → Line

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The bag's velocity when a bag is dropped from a hovering helicopter is 15.68m/s

Its initial velocity is zero. In a free-falling body, the value of the final velocity is obtained through the equation

                                           Vf =u + gt

u = o ( because the bag is dropped, so it falls starting from rest)

Vf = gt

u is initial velocity

Vf is final velocity

t is time

where g is the acceleration due to gravity, 9.8 m/s².

using above values we get

 Vf = (9.8 m/s²)(1.6s)

= 15.68m/s

The bag's velocity when a bag is dropped from a hovering helicopter is 15.68m/s

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Answer:

TRUE

Explanation:

Organs are made of two or more tissue types to allow them to function.

Hope this helps! :D

After moving, the two point charges are 6.36 cm apart.

We know that,

F = k [tex]q_{1} q_{2}[/tex] / [tex]r^{2}[/tex]

where,

[tex]q_{1} q_{2}[/tex] = two point charges

k = Coulombs constant

r = Distance between two charges

F = Electrostatic force between two charges

Given that,

r = 9 cm

F = k [tex]q_{1} q_{2}[/tex] / [tex]9^{2}[/tex]

[tex]F^{'}[/tex] = 2F

k [tex]q_{1} q_{2}[/tex] / [tex]r'^{2}[/tex] = 2 * k [tex]q_{1} q_{2}[/tex] / [tex]9^{2}[/tex]

[tex]r'^{2}[/tex] = 81 / 2 = 40.5

r' = 6.36 cm

Electrostatic force is the force between two point charges. It can either be positive or negative. If negative the forces are attractive and if positive the forces are repulsive in nature.

Therefore, after moving, the two point charges are 6.36 cm apart.

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The final pressure is 6.96 atm.

We know that in an adiabatic process,

[tex]p_{1} V_{1} ^{gamma}[/tex] = [tex]p_{2} V_{2} ^{gamma}[/tex]

where,

p = Pressure

V = Volume

Gamma = Isentropic expansion factor

Given that,

[tex]p_{1}[/tex] = 1 atm

γ = 1.4 ( Assuming the air as an ideal gas )

[tex]V_{2}[/tex] = [tex]V_{1}[/tex] / 4

[tex]V_{1}[/tex] / [tex]V_{2}[/tex]  = 4

[tex]p_{1} V_{1} ^{1.4}[/tex] = [tex]p_{2} V_{2} ^{1.4}[/tex]

[tex]p_{2}[/tex] = 1 * [tex]( 4 )^{1.4}[/tex] = 6.96 atm

An adiabatic process is a thermodynamic process without the involvement of heat. Usually it takes place in an insulated box.

Therefore, the final pressure is 6.96 atm

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The driver drives at a speed of 20km/hr, then the average speed is 24km/hr.

According to the question, they traveled one kilometer at a speed of 20 kilometers per hour. The equation time = distance/speed can be used to determine how long it will take to travel this distance. Thus, the duration of the initial leg of the journey is 1/20, or 0.05 hours.

then proceeded to travel at a speed of 30 km/h for an additional distance of 1 km. Similar to the previous section, this one's travel time is 1/30, or 0.0333 hours.

Now, add the travel times for both legs to get the overall time: 0.05 + 0.0333 = 0.0833 hours.

Now, adding the distances covered in each leg of the journey to get the total distance traveled: 1 + 1 = 2 kilometers.

By dividing the total distance by the total time, we can finally determine the average speed: average speed = total distance/total time = 2/0.0833 24 km/h.

As a result, they travel at a speed of roughly 24 km/h.

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The distance of the point from the axis of rotation of the second hand is 9.1 m.

The point from the axis of rotation of the second hand is the radius of the rotation of the clock.

a = v²/r

v² = ar

v = √ar

V = [tex]\frac{2\pi r}{T}[/tex]

√ar = [tex]\frac{2\pi r}{T}[/tex]

ar = [tex]\frac{4\pi^2 r^2}{T^2}[/tex]

a = [tex]\frac{4\pi^2r}{T^2}[/tex]

r = [tex]\frac{aT^2}{4\pi^2}[/tex]

r = (0.1 x 60²)/(4π²)

r = 9.1 m

Newton’s second law states that when a body is subjected to an external force, it begins to accelerate.

The only thing that constitutes acceleration is a change in an object’s velocity over time. It carries both magnitude and direction as a vector quantity.

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Measuring human impact and comparing it with the biophysical world's carrying capacity is known as Ecological footprint.

The Global Footprint Network promotes the ecological footprint as a way to assess how much nature is needed to sustain a certain number of people or an economy. Through an ecological accounting system, it monitors this demand. The accounts compare the biologically productive areas used by people for consumption to the biologically productive areas available in a region or throughout the world (biocapacity, the productive area that can regenerate what people demand from nature). It measures the effects of humans on the environment, to put it briefly.

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Cepheids cataclysmic variables object is the period-luminosity relation used for determining distances.

Cepheid Variables are very bright stars that are 500–300,000 times as bright as the sun. They undergo brief variations every 1–100 days. They are pulsing variables that follow a predetermined pattern and experience rapid expansion and contraction. Other pulsating variables include RR Lyrae stars, which are short period, older stars that are not as massive as Cepheids; and RV Tauri stars, which are super giants with higher light fluctuations. Astronomers may study the variability of a Cepheid's brightness to determine its distance.

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The three equations for describing free-falling objects in gravitational fields are given below:

Free fall refers to the motion of a body that is at a certain height above the surface of the earth and which is allowed to fall or move vertically downwards under the influence of gravity alone.

Gravity is the attractive force with which the earth attracts objects to its surface.

Objects that are attracted to the surface of the earth by gravity are given an acceleration g, known as acceleration due to gravity.

The value of the acceleration due to gravity, g = 9.8 m/s²

The equations for describing free-falling objects in gravitational fields are given below:

where;

h = height above ground

u is the initial velocity

v s final velocity

t is time

g is to acceleration due to gravity

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The magnitude of the seal's displacement will be 486.41m

There are an endless number of paths that can be built between two places. The distance is the name given to any specific length of path. There is a path with the shortest distance out of all of these, and the length of that path is determined by the size of a properly specified vector quantity called the displacement.

Given that an elephant seal goes 311 m to the east of his starting location when diving to a depth of 374 m.

Allow the seal to begin at point A and dive deep to reach position B. In the illustration below, his displacement is highlighted in red:

The hypotenuse of the right triangle ABC can be located to determine the displacement's magnitude.  

We discover:

displacement of the seal = [tex]\sqrt374^{2} +311^{2} = 486.41m[/tex]

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The dielectric strength of a dielectric substance is equal to the greatest magnitude of the external electric field that does not cause electrical breakdown. When an electric field is applied to a dielectric, the dielectric will transform into a conductor at a point known as electrical break down.

Given that

A parallel plate capacitor consists:

Capacitance Co

Plates of Area A

Separation distance between the plates d

Voltage of a battery Vo

Magnitude of charge Qo

Dielectric constant K=3

the capacitance of parallel plate capacitor when there is free space between the plates is given by

Co = εoA/d

Where εo is permittivity of free space.

If the battery is connected to the parallel plate capacitor, the gap between the plates is filled with dielectric constant. The capacitance of the parallel plate capacitor for the medium will then be determined.

a) C=KεoA/d

=3εoA /d

=3 Co

Now, the potential difference between the plates will be

b) Vo =QC

Vo=QC

Hence, the magnitude of charge by adding dielectric medium will be

c) Q= CVo

=3εoA Vo /d

=3 Co Vo

=3 Qo

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On a circle of radius r, a central angle of radians subtends an arc of length(s) is r; the area of the sector formed by this angle is a 12r2Θ. The central angle of radians subtends an arc of length(s) that is multiple of radius (r) and central angle().

The concept of area is always associated with two dimensions. Any two-dimensional object can combine to form a plane. As a result, every two-dimensional figure has an area. Every point in a plane that is a particular distance away from some other point forms a circle. The circle's radius and fixed distance are both referred to as the circle's center and radius, respectively.

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When the cart travels towards the origin, the magnitude of its exact position reduces with time.

The cart will be at -2 m (origin) 2s later.

When the cart travels towards the origin, the magnitude of its exact position reduces with time.

The formula of speed is given as

S = d/t ................. (1)

Where S = speed of the cart,

d = distance covered by the cart over a certain time.

t = time taken to cover the distance.

Where d the subject of the equation,

d = St ................. (2)

Given: S = 2.0 m/s, t = 2.0 s

Substitute into (2)

d = 2(2)

d = 4 m.

From the above, the cart covered a distance of 4 m in 2s.

The exact position of the cart = Initial position - distance covered

x' = x - d ............ (3)

Where x' = exact position of the cart 2s later,

x = initial position of the cart, and

d = distance covered by the cart in 2.0 s

Given: x = 2.0 m, d = 4 m.

Substitute into (3)

x' = 2.0 - 4

x' = -2 m.

Therefore the cart will be at -2 m (origin) 2s later.

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The resultant pH= 4.95

A weak acid solution and a conjugate base solution can be combined to create a buffer.

Strong acid or strong base addition does not result in a significant pH shift when a weak acid and conjugate base are present in the solution.

A buffer's pH can be determined using the Henderson-Hasselbalch equation:

pH = Pka + log [base] / [acid]

Let 0.05-x represent the amount of acetate in the buffer and x represent the amount of acetic acid in the buffer.

5.2 = 4.75 + log 0.05− x / x

0.05− x = 0.0369 M

HA = 0.0130 M × 800 mL+ 50 mL× 0.1 M = 15.47 mmol

A = 0.0369 M× 800 mL− 50 mL×0.1 M = 24.52 mmol

The new pH is:

pH= 4.75 + log 25.42 / 15.47

pH= 4.95

The resultant pH of the solution= 4.95

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An good example would be using a Bunsen burner to heat water in a tin container. The flame initially heats the tin can by radiating heat. Conduction then transfers heat from the tin can to the water. The convection process causes the hot water to then climb to the top.

A laboratory piece of equipment known as a Bunsen burner, which bears Robert Bunsen's name, produces a single open gas flame and is used for heating, sterilization, and combustion. Natural gas, liquefied petroleum gas, such as propane, butane, or a combination, are all acceptable choices for the gas.

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The distance from the center of a lens to the point at which light rays converge on the film is known as the focal length of the lens.

In photography, focal length is the distance measured in millimeters (mm) between the optical center of the lens and the camera sensor, where the light information is recorded.

It is important because it dictates the distance your camera will be able to capture. Smaller numbers show more scene and have wider angle while larger numbers show less scene and have tighter angle of view.

The process of recording an image on light-sensitive film is known as photography.

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1.6 ms-1 was their initial velocity when they kicked off.

The velocity at time interval t = 0 is indicated by the symbol u. It is the speed at which the motion begins. Because the length of the pool is not given, the width is used to estimate the distance travelled;

Length of a swimming pool =8 m

A swimmer crosses it and then makes their way across

Total distance covered =8×2=16 m

Time taken =10 seconds

Initial velocity = distance/ time

=16/10

=1.6 ms-1

Therefore, the initial velocity is 1.6 ms-1. Note the question requested initial velocity since it is impossible to estimate the final velocity of the swimmer as he maintains a constant rate across the pool when swimming back.

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Acceleration is not the same as speeding up. It refers to any modification of motion's direction or speed. Accelerated motion is any movement that is not constant speed in a straight line.

In physics, acceleration refers to the rate at which an object's velocity over time changes. They are accelerations and vector quantities. The direction of an object's acceleration is determined by the direction of the net force acting on it.

Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change. Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign.

Acceleration is the measure of a change in velocity. Acceleration frequently, though not always, denotes a shift in speed. The direction of motion is changing, therefore an object moving at a constant speed in a circular path is still moving ahead.

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The final speed of an airplane is v = 92.95 m/s

The rate of change of position of an object in any direction is known as speed i.e. in other word, Speed is measured as the ratio of distance to the time in which the distance was covered.

Solution-

Here given,

Acceleration a= 10.8 m/s2 .

Displacement (s)= 400m

Then to find final speed of airplane v=?

Therefore from equation of motion can be written as,

v²=u²+ 2as

where, u is initial speed, v is final speed ,a is acceleration and s is displacement of the airplane. Therefore by putting the value of a & s in above equation and (u =0) i.e. the initial speed of airplane is zero.

v²= 2×10.8 m/s²×400m

v²=8640m/s

v=92.95m/s

hence the final speed of airplane v =92.95m/s

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Answer:

New concentration of A =3 [A] Put the values we get new rate of reaction. − dtd[R]=k[3A] 2[B] Hence, the rate of reaction will increase by 9 times. (iii) Given that. New concentrations of A=2[A] New concentration of B=2[B] Plug the values we get.

Explanation:

The rate using the rate constant and the given concentrations [tex]\( \text{rate} = 2.1897 \text{ mol/L.s} \)[/tex].

The rate law for the reaction is given as: [tex]\rm \[ \text{rate} = k \times [a]^2 \times [b] \][/tex]

where:

[tex]\[ [a] = 4.11 \text{ mol/L} \]\\\ [b] = 3.71 \text{ mol/L} \][/tex]

[tex]\rm \[ k \][/tex] is the rate constant (to be determined)

To find the rate, we need to calculate the rate constant [tex](\( k \))[/tex] and then substitute the given concentrations of [tex]\( [a] \)[/tex] and [tex]\( [b] \)[/tex] into the rate law.

Step 1: Calculate the rate constant [tex](\( k \))[/tex] using the provided rate value and concentrations.

[tex]\[ \text{rate} = 2.1897 \text{ mol/L.s} \]\\\[k = \frac{\text{rate}}{[a]^2 \times [b]} \]\[k = \frac{2.1897 \text{ mol/L.s}}{(4.11 \text{ mol/L})^2 \times 3.71 \text{ mol/L}} \][/tex]

Step 2: Calculate the rate using the rate constant and the given concentrations.

[tex]\[ \text{rate} = k \times [a]^2 \times [b] \]\[ \text{rate} = \left(\frac{2.1897 \text{ mol/L.s}}{(4.11 \text{ mol/L})^2 \times 3.71 \text{ mol/L}}\right) \times (4.11 \text{ mol/L})^2 \times 3.71 \text{ mol/L} \]\[ \text{rate} = 2.1897 \text{ mol/L.s} \][/tex]

The correct result is [tex]\( \text{rate} = 2.1897 \text{ mol/L.s} \)[/tex].

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The charge that has passed through the element the first millisecond is 2.3nc.

Millisecond is a period estimation unit with the image of MS, which is equivalent to a one thousandth of a second. It can likewise be characterized as the span of photograph electric lamp, or as the hour of a cycle for 1kHz recurrence. This unit is at times utilized while estimating extent or making truly exact physical and logical computations. Millisecond is clearly utilized rigorously for logical purposes since estimating this unit of time is very troublesome. This web-based milliseconds to microseconds converter can be exceptionally helpful for understudies, analysts, science fans and the people who are needing making time changes.

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The maximum allowable percentage change is 3.8% in the string tension

Length of the string lg as given in the question = 0.350m

frequency of concert G f_g as given in the question= 392 Hz

The maximum allowable percentage change in string tension for this frequency remains constant and the given allowed interval of the change of the length

Formulating the equation and solving:

Let f be the frequency, T be the tension and U be the length of the wave

f = 1/2L*[tex]\sqrt{} T/U[/tex]

df = 1/2[tex]\sqrt{} U[/tex]*[tex](1/2\sqrt{}T- Ldt - dL\sqrt{}T)/L^{2}[/tex]

df = 0

dT/T = 2*(dL/L)

= 2*0.6/31.2

dT/T = 0.038

Percentage change in string tension 3.8%

The maximum percentage change in string tension is 3.8%

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