DIG DEEPER The diagram shows the elevation changes between checkpoints on a trail.

A drawing shows the change in elevation between checkpoints on a mountain trail. From a point labeled start, the trail moves down to a point which is labeled negative 174 feet from the starting point. The trail then moves upward up to a point labeled 350 feet above the previous point. Next, the trail moves down to a point which is labeled negative 180 feet below the previous point. Then the trail moves up to a point labeled 282 feet above the previous point labeled end.

The trail begins at an elevation of 8136 feet. What is the elevation at the end of the trail?

The elevation is
feet.
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Answer:

[tex]\large\boxed{\textsf{The Circumference is the Perimeter of the circle.}}[/tex]

Step-by-step explanation:

[tex]\textsf{We are asked to identfy what the Circumference is.}}[/tex]

[tex]\Large\underline{\textsf{What is the Circumference?}}[/tex]

[tex]\textsf{The Circumference is a fancy word to describe the sum of the arcs of a circle.}[/tex]

[tex]\textsf{The total of the area 'on' the circle is commonly referred to as the Perimeter.}[/tex]

[tex]\mathtt{Circumference = (diameter)\pi }[/tex]

The solution for the expression {8 ( 29 - 7 * 4 ) / ( 7 + 4 - 8 + 1 } - 3 ( 2 ) / 6 will be 1.

We are given the expression:

{8 ( 29 - 7 * 4 ) / ( 7 + 4 - 8 + 1 } - 3 ( 2 ) / 6

We will solve this expression by using the property of PEMDAS:

Solving the expression , we get

{8 (29 - 28) / 11 - 8 + 1} - 3 (2) / 6

= (8 × 1) / 4  -( 6 / 6)

= 2 - 1

= 1

Therefore, the solution for the expression {8 ( 29 - 7 * 4 ) / ( 7 + 4 - 8 + 1 } - 3 ( 2 ) / 6 will be 1.

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Answer:  m 21=

I got it right on test!

Step-by-step explanation:

Applying the angle relationship, the measures of the angles are:

m<a = 126°

m<b = 54°

m<c = 126°

m<d = 54°

m<e = 126°

m<f = 54°

m<g = 126°

The diagram shows different angles that are formed when a transversal crosses two parallel lines. To find the measure of the missing angles, we would apply the angle relationship.

m<a = 180 - 54 [linear pair]

m<a = 126°

m<b = 54° [vertical angles pair]

m<c = m<a [vertical angles pair]

m<c = 126°

m<d = 54° [corresponding angles]

m<e = m<a [corresponding angles]

m<e = 126°

m<f = m<d [vertical angles pair]

m<f = 54°

m<g = m<e [vertical angles pair]

m<g = 126°

Therefore, applying the angle relationship, the measures of the angles are:

m<a = 126°

m<b = 54°

m<c = 126°

m<d = 54°

m<e = 126°

m<f = 54°

m<g = 126°

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Answer:

n = 3p

Step-by-step explanation:

12n + 7p - 6n = 25p

12n - 6n +7p = 25p

12n - 6n = 25p - 7p

6n = 18p

[tex]n=\frac{18p}{6}[/tex]

n = 3p

Ricky had 176 cookies initially

Let Ricky has x number of cookies

Cookies left after he ate 1/8 of his cookies and additional 14 cookies:

x - (1/8x + 14)

Cookies left after he ate 3/10 of the remaining cookies and an additional 24 cookies on Saturday:

x - (1/8x + 14) - 3/10(x - (1/8x + 14)) + 24)

Cookies left after he ate 40 more cookies on Sunday

x - (1/8x + 14) - 3/10(x - (1/8x + 14)) + 24) - 40 ------(1)

Cookies left with him at the end = 34

Therefore, equating equation (1) with 34

(7/10)((7x/8) - 14) - 64 = 34

x = 176

Thus Ricky had 176 cookies intially

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[tex] \large \bf \implies{15}[/tex]

[tex]\bf \longrightarrow((2 + 4 \times 2) - 5) \times 3[/tex]

Step 1) ; Calculate the product or quotient

[tex]\bf \longrightarrow((2 + 8) - 5) \times 3[/tex]

Step 2) ; Calculate the sum or difference

[tex]\bf \longrightarrow(10 - 5) \times 3[/tex]

Step 3) : Calculate the sum or difference

[tex]\bf \longrightarrow5 \times 3[/tex]

Step 4) : Calculate the product or quotient

[tex]\bf \longrightarrow15[/tex]

The mathematical expression can be written as [tex]5(x+7)-4^3[/tex]

Any combination of terms that have undergone operations like addition, subtraction, multiplication, division, etc. is known as an algebraic expression (or variable expression). Let's use the equation 5x + 7 as an example. Thus, 5x + 7 is an illustration of an algebraic expression.

We frequently have to understand a written phrase in order to write an expression. For instance, the notation x + 6 can be used to represent the phrase "6 added to some number," where x stands for the unknown value.

The algebraic properties most frequently utilized to simplify algebraic statements are associative, commutative, and distributive.

Here the quantity x is increased by 7 and the sum is multiplied by 5.

so we get 5(x+7).

Now 4 cubed is subtracted from the resulting expression.

Therefore the expression looks like [tex]5(x+7)-4^{3}[/tex] .

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According to the cross product, The value of x in the expression becomes 16.

According to the statement

We have to find that the value of the expression.

So, For this purpose, we know that the

Cross product is a binary operation on two vectors in three-dimensional space.

From the given information:

The expression is a

StartFraction 4 over 3 EndFraction = StartFraction x over 12 EndFraction

IN simple words, it becomes:

4/3 = x/12

Then we have to find the value of the x then

4/3 = x/12

Now cross multiply each other then

4 =3x/12

3x = 48

Then

x = 48/3

x = 16.

So, According to the cross product, The value of x in the expression becomes 16.

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Answer:

Please see the picture below.  You were on the right track.  You were just off in letter A.

Step-by-step explanation:

An infant may have had birthing complications that reduced the amount of oxygen in her blood if her Apgar score ranges from 7 at 1 minute to 9 at 5 minutes. In this situation, the hospital nurses will most likely vigorously dry her with a towel while holding oxygen under her nose.

The Apgar score is a recognized and practical way to report on the newborn baby's condition right after birth and their reaction to resuscitation, if necessary. One's particular neonatal mortality or neurologic prognosis cannot be predicted by the Apgar score alone, nor can it be regarded as a result of suffocation. It should also not be utilized to do so. An infant's spontaneous breathing score and the Apgar score given after resuscitation are not the same thing. An enhanced Apgar score reporting form that takes into account concurrent resuscitative treatments is encouraged by both the American Academy of Pediatrics and the American College of Obstetricians and Gynecologists.

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Answer:

(4), -5/6

Step-by-step explanation:

[tex]13-36x^2-13=-12-13\\-36x^2=-25\\\frac{-36x^2}{-36}=\frac{-25}{-36}\\x^2=\frac{25}{36}\\x=\sqrt{\frac{25}{36}},\:x=-\sqrt{\frac{25}{36}}[/tex]For x^2 = f(a), x = f(a), -f(a)

[tex]x=\sqrt{\frac{25}{36}},\:x=-\sqrt{\frac{25}{36}}\\\sqrt{\frac{25}{36}}\\\sqrt{25}\\\sqrt{5^2}=5\\=\frac{5}{\sqrt{36}}\\\sqrt{36}\\=\sqrt{6^2}=6\\=\frac{5}{6}[/tex]

Reverse the same equation from the negative side

[tex]=-\frac{\sqrt{25}}{\sqrt{36}}\\\sqrt{25}\\=\sqrt{5^2}\\=5\\=-\frac{5}{\sqrt{36}}\\\sqrt{36}\\=\sqrt{6^2}\\=6\\=-\frac{5}{6}[/tex]

Therefore,

[tex]x=\pm\frac{5}{6}[/tex]

Answer:

-5,-1

Step-by-step explanation:

add 4 to get the next number

1 hour & 45 minutes is the distance between his home and school.

What is distance short answer?

d=rt

distance = rate of speed times time

d= 33X = 44(7/4-X)

33X = 77- 44X

77X = 77

X = 1 hour

33X = 33 miles

44(7/4 - 4/4) = 33 miles each way

1 hour & 45 minutes = 1 3/4 hours or 7/4 hours

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A new apple orchard is being planted by Aaron's uncle. They plant 12 trees after picking up a truckload of them. They still need to plant 40 trees the following day.

The letter (N) is the symbol used to represent natural numbers. Natural numbers are also known as counting numbers, and they begin with the number 1 and continue to infinity (never ending), which is represented by three dots (...)

900n - 9[tex]n^2[/tex] = A(n) = n(900 - 9n)

For the highest A(n), A'(n) = 0, A'(n) = 900 - 18n = 0, 18n = 900, and n = 900/18 = 50.

50 trees should be planted per acre to produce the most apples possible

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b: 3 x 10 to the power of 7

can you please give brainliest

[tex](-1)x\times(-1)^{12}\implies -x\times(-1)^{2+2+2+2+2+2} \\\\\\ -x\times(-1)^2 (-1)^2 (-1)^2 (-1)^2 (-1)^2 (-1)^2 \implies -x\times 1\cdot 1\cdot 1\cdot 1\cdot 1\cdot 1\implies -x[/tex]

bear in mind that any value raised to an even power, will always positivize.

The Solution in inequality form is 7 ≤ x ≤ 10.

The Solution in interval notation: [7,10].

Given the data in the question;

-x - 8 ≤ -15 and -18 ≤ -x - 8

To solve, simplify the first part of the inequality by solving for x.

-x - 8 ≤ -15

Add 8 to both sides

-x - 8 + 8 ≤ -15 + 8

-x ≤ -7

Divide both sides by -1

Note that when dividing both sides of an inequality by a negative value, the inequality sign flips direction.

-x/-1 ≥ -7/-1

x ≥ 7

Next, simplify the second part of the inequality by solving for x

-18 ≤ -x - 8

Rewrite as

-x - 8 ≥ -18

Add 8 to both side

-x - 8 + 8 ≥ -18 + 8

-x ≥ -10

Divide both sides by -1

Note that when dividing both sides of an inequality by a negative value, the inequality sign flips direction.

-x/-1 ≤ -10/-1

x ≤ 10

Now, the intersection consist of the elements that are contained in both intervals.

The Solution in inequality form is 7 ≤ x ≤ 10.

The Solution in interval notation: [7,10].

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3. (-1,-2), (0,-1), (1,0), (2,1), and (3,2)

3. (0,0), (-1,2), (1,2), (-2,4), and (2,4)

Answer: -17

Step-by-step explanation:

-3^2 + -5^2/ -3 - (-5)

-34 / -3 - (-5)

-34/2

-17

Answer:

[tex]\dfrac{5x^2+20x+16}{x(x+1)^2} & \equiv \dfrac{16}{x}-\dfrac{11}{(x+1)}-\dfrac{1}{(x+1)^2}[/tex]

Step-by-step explanation:

When writing an algebraic fraction as an identity, if its denominator has repeated linear factors, the power of the repeated factor indicates how many times that factor should appear in the partial fractions.

Write out the fraction as an identity:

[tex]\begin{aligned}\dfrac{5x^2+20x+16}{x(x+1)^2} & \equiv \dfrac{A}{x}+\dfrac{B}{(x+1)}+\dfrac{C}{(x+1)^2}\\\\\implies \dfrac{5x^2+20x+16}{x(x+1)^2} & \equiv \dfrac{A(x+1)^2}{x(x+1)^2}+\dfrac{Bx(x+1)}{x(x+1)^2}+\dfrac{Cx}{x(x+1)^2}\\\\\implies 5x^2+20x+16 & \equiv A(x+1)^2+Bx(x+1)+Cx\end{aligned}[/tex]

Calculate the values of A and C using substitution:

[tex]\begin{aligned}\textsf{When }x=0 \implies 16 & =A(1)+B(0)+C(0) \implies A=16\\\\\textsf{When }x=-1 \implies 1 & =A(0)+B(0)+C(-1) \implies C=-1\end{aligned}[/tex]

Substitute the found values of A and C and expand the identity:

[tex]\begin{aligned}\implies 5x^2+20x+16 & \equiv 16(x+1)^2+Bx(x+1)-x\\& \equiv 16x^2+32x+16+Bx^2+Bx-x\\& \equiv (16+B)x^2+(31+B)x+16\\\end{aligned}[/tex]

Compare the coefficients of the x² term to find B:

[tex]x^2 \textsf{ term } \implies 16+B =5\implies B & =-11[/tex]

Replace the found values of A, B and C in the original identity:

[tex]\dfrac{5x^2+20x+16}{x(x+1)^2} & \equiv \dfrac{16}{x}-\dfrac{11}{(x+1)}-\dfrac{1}{(x+1)^2}[/tex]

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Answer:

Step-by-step explanation:

the answer is simply 2

The answer will be  : x = -- 3y -- 9

⇒ -2 (x + 3y) = 18

⇒ -(2x + 2 * 3y) = 18

⇒ -(2x + 6y) = 18

⇒ (-2x -6y) + 6y = 18 + 6y

⇒ -2x -6y + 6y = 6y + 18

⇒ -2x = 6y + 18

⇒ [tex]\frac{2x}{2} = \frac{-6y + 18}{2}[/tex]

⇒ [tex]x = \frac{-(2*3)y + (2*3)^{2} }{2}[/tex]

⇒ [tex]\frac{-2*3\frac{2*3y}{2*3} + \frac{(2*3)^{2} }{2*3} }{2}[/tex]

⇒ [tex]x = \frac {2*3(y + (3)^{2 - 1}) }{2}[/tex]

⇒ [tex]x = \frac{-2*3(y + 3)}{2}[/tex]

⇒ x = -[3(y + 3)]

⇒ x = (3y + 3*3)

⇒ x = -(3y + 9)

⇒ x = - 3y - 9

WORKING NOTES :

-2 (x + 3y) = 18

[We must multiply a term and an expression in order to enlarge this word.

We'll utilize the following product distributive property:

A(B + C) = AB + AC

⇒ -(2x + 2 * 3y) = 18

The final expression, in this case, will have two terms:

The first term is a product of '2' and 'x'

the second term is a product of '2' and '3y'.]

In this term, numerical components have been multiplied.

⇒ -(2x + 6y) = 18

We must group all the variable terms on one side of the equation and all the constant terms on the other in order to solve this linear equation.

⇒ (-2x -6y) + 6y = 18 + 6y

Here, the '-' (minus)  term, -6y will be moved to the right side.

When a term "moves" from one side of the equation to the other, you'll notice that its sign changes.

Parentheses around expressions must be eliminated.

Each term in the expression changes sign if a negative sign is placed in front of it. Otherwise, the expression stays the same.

There is no negative sign in the situation.

⇒ -2x -6y + 6y = 6y + 18

In order to join like terms in this expression, we must first sum all of the numerical coefficients and, if necessary, replicate the literal section.

Nothing in a number suggests a value of 1.

There is just one set of related terms: -6y, 6y.

⇒ -2x = 6y + 18

We must eliminate the coefficient that multiplies the variable in this linear equation in order to isolate it.

If both sides are divided, then the coefficient must be removed (-2)

⇒ [tex]\frac{2x}{2} = \frac{-6y + 18}{2}[/tex]

We must simplify this fraction to its simplest form.

To do this, divide the variables that occur in both the numerator and the denominator.

The common factor, in this case, is 2.

⇒ [tex]x = \frac{-(2*3)y + (2*3)^{2} }{2}[/tex]

We must consider the GCF (Greatest Common Factor).

The GCF and the original expression, split by the GCF, provide the final term.

⇒ [tex]\frac{-2*3\frac{2*3y}{2*3} + \frac{(2*3)^{2} }{2*3} }{2}[/tex]

GCF in this case is 2*3.

The fraction [tex]\frac{2*3y}{2*3}[/tex] must be lowered to its simplest form. To do this, divide the variables that occur in both the numerator and the denominator.

Here, the common factor is 2*3.

⇒ [tex]x = \frac {2*3(y + (3)^{2 - 1}) }{2}[/tex]

The expression must be lowered to its simplest form.

Driving out the components that exist in both the numerator and the denominator will accomplish this.

2*3 is a common factor.

⇒ [tex]x = \frac{-2*3(y + 3)}{2}[/tex]

Numerical terms in the factor {y + (3²⁻¹)} is added which makes it (y + 3)

The fraction will then be broken down into its smallest terms next.

To do this, divide the variables that occur in both the numerator and the denominator.

2 is the common factor.

⇒ x = -[3(y + 3)]

⇒ x = -(3y + 3*3)

We must multiply a term and an expression in order to expand this term.

We'll utilize the following product distributive property:

A=AB+AC = A(B + C)

The final expression, in this case, will have two terms:

"3" and "y" are the product in the first term.

The second term is the result of the numbers 3 and 3.

⇒ x = -(3y + 9)

This term's numerical terms have been multiplied by three (3*3 = 9).

⇒ x = - 3y - 9

The parenthesis around expressions must be eliminated.

Each term in the expression changes sign if a negative sign is placed in front of it.

Otherwise, the expression stays the same.

The signs of the following two terms will now change. -(3y + 9) = - 3y - 9

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The points where the graph intercepts the x-axis is the root of the function.

from the graph the points are 3.9 and 6.1

The vertex v is at v ( 5, -4 ) this is equivalent to v ( h, k )

the equation of parabola in vertex form is y = a ( x- h )^2 + k

y = a ( x - 5 )^2 + {-4)

substituting point ( 4, -1 ) from the graph we have:

-1 = a ( 4 - 5 )^2 - 4

-1 = a - 4

a = 3

substituting the known values to y = a ( x- h ) + k

y = 3 ( x - 5 )^2 - 4

y = 3 ( x - 5) ( x - 5 ) - 4

y = 3 ( x - 5) ( x - 5 ) - 4

y = 3 ( x^2 - 10x + 25 ) - 4

y = 3x^2 - 30x + 75 - 4

y = 3x^2 - 30x + 71

The points where the graph intercepts the x-axis is the root of the function.

from the graph the points are 2 and 4

The vertex v is at v ( 3, 2 ) this is equivalent to v ( h, k )

the equation of parabola in vertex form is y = a ( x- h )^2 + k

y = a ( x - 3 )^2 + 2

substituting point ( 0, -16 ) from the graph we have:

-16 = a ( 0 - 3 )^2 + 2

-16 = a - 9 + 2

-16 = a - 7

a = -9

substituting the known values to y = a ( x- h ) + k

y = -9 ( x - 3 )^2 + 2

y = -9 ( x - 3) ( x - 3 ) + 2

y = -9 ( x - 3) ( x - 3 ) + 2

y = -9 ( x^2 - 6x + 9 ) - 4

y = 3x^2 - 54x - 81 - 4

y = 3x^2 - 54x - 85

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The difference between the two prime numbers 17 and 39 is 22.

Prime numbers are those who have only two factors: 1 and the number on its own.

For the number given:

22 17 25 41 39 4

The two primes numbers are 17 and 39.

The difference is 39 - 17 = 22.

Thus, the difference between the two prime numbers is 22.

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(q ∨ (¬r ∧ ¬q)) → ¬p is the propositions and create logic sentences.

What is propositions ?

An axiom is a mathematical assertion that is predicated on a proposition, such as "3 is greater than 4," "an infinite set exists," or "7 is prime."

If you are more than  18 years old or if you are above 18 but lack identification proving your age, you are not permitted to to watch cartoon.

Prepositions -

p = You are allowed to watch cartoon.

q = your age is more  than 18 years old

r = you have age proof

(q ∨ (¬r ∧ ¬q)) → ¬p

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y - 11 = -3 ( x + 2) is the equation in point-slope form of the line .

What is slope ?

Given points :  (0, 5) and (−2, 11)

Slope of the line passing through given points

[tex]m = \frac{y_{2}- y_{1} }{x_{2} - x_{1} } = \frac{11 - 5}{-2 - 0} = \frac{6}{-3} = -3[/tex]

Thus, slope of line passing through given points m=-3

We know that the equation of a line passing through points ( x₀ , y₀) with slope 'm' is ( y - y₀ ) = m(x - x₀)

Thus, equation of a line passing through (−2, 11) with slope m=-3 will be

( y - 11 ) = -3 ( x - (-2))

y - 11 = -3 ( x + 2)

Hence, the equation of line is y - 11 = -3 ( x + 2).

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Answer:

4c + 8 = 20

Step-by-step explanation:

To find which equation is true, we have to plug 3 into x in each equation.

2c + 8 = 31

Plug in 3 into c

2(3) + 8 = 31

6 + 8 = 31

14 = 31

Since 14 doesn't equal 31, this equation isn't true.

35 − 5c = 32

Plug in 3 into c

35 − 5(3) = 32

35 - 15 = 32

20 = 32

Since 20 doesn't equal 32, this equation isn't true.

9 − 6c = 0

Plug in 3 into c

9 − 6(3) = 0

9 − 18 = 0

-9 = 0

Since -9 doesn't equal 0, this equation isn't true.

4c + 8 = 20

Plug in 3 into c

4(3) + 8 = 20

12 + 8 = 20

20 = 20

Since 20 equals 20, this equation is true.

Have a lovely rest of your day! :)

The value of g(-4) is 8.

A set of inputs and outputs that are connected to one another in some way is referred to as a relation. We refer to the relations as a function when each input results in a single output. However, you must be certain that no input leads to more than one output in order to determine if a relation is a function or not.

Only when each element of a nonempty set M has a single range to a nonempty set N is a function a relation.

g(x) = ax^2 + 24

⇒ g(4) = a (4)^2 + 24

⇒ 8 = 16a + 24

⇒ 8 − 24 = 16a

⇒ −16 = 16a

⇒ a = −1

Since, g(−4) = a(−4) ^2 + 24

∴ g(−4) = 16(−1) + 24

⇒ g(−4) = 8

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