Mass of kool aid required is 3.42g to make 0.2 mole solution 1 liter
by the formula of molarity we know that molarity = mole/liter
We can enter those values into the equation to determine the necessary number of moles because we know that we want a 0.1Mole solution in 100 mL so by substituting the values 1/ 0.1= 0.01 moles.
We now know that there are 0.01 moles of Kool-Aid powder. Additionally, we are aware that this powder's chemical composition is c12 h22o11
By multiplying the atomic weight from the periodic table by the quantity of atoms in the compound, we may determine the molar weight of this powder. Let's calculate the powder's molar weight:
Find the carbon atomic weight
12 X 12 =144g
Then we have 22 H's, each having an atomic weight of 1.008g
22 X 11= 22g
And finally there are 11 O's, each with an atomic weight of 16g
16 X11 =176g
by adding the atomic weight of atoms 342.19g
now by finding the grams of kool compound 342.19 X 0.01mol = 3.42g.
now we know that we need 0.01 moles of the powder, and we need 3.42g of the powder to make the desired solution
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Hydrogen sulfide gas is reacted with dioxygen gas to produce gaseous sulfur dioxide and water. True or false?.
Hydrogen sulfide gas is reacted with dioxygen gas to produce gaseous sulfur dioxide and water. It is false.
When hydrogen sulfide gas reacts with dioxygen gas, it produces water and solid Sulphur and not gaseous sulfur. The chemical equation of the given substances is :
2H2S + O2 → 2S + 2H20
It is a redox reaction as both Oxidation and reduction happens in it. Oxidation of hydrogen sulphur to sulphur happens and reductions of oxygen to water takes place.
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A p orbital has _____ regions or lobes of high electron probability, on either side of the nucleus. this gives the orbital a(n) _____ shape.
A p orbital has two regions or lobes of high electron probability, on either side of the nucleus. This gives the orbital dum-bb-ell shape.
The p - orbital is the atomic orbital consist of two sections called lobes on either side of plane passing trough nucleus and the shape of p - orbital appears as dum-bb-ell.
The region around the nucleus is where the probability of electron finding is high and called as orbital. The p orbital lobed region is where their is high probability of finding an electron. The probability of finding electron in the nucleus is very low .
Hence, A p orbital has two regions or lobes of high electron probability, on either side of the nucleus. This gives the orbital dum-bb-ell shape.
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What would this frequency become if the person's breathing passage were filled with helium instead of air? assume the same temperature dependence for helium as for air.
1.07×10³Hz frequency become if the person's breathing passage were filled with helium instead of air
Here, air temp is taken as 37.0°C if the person's breathing passage were filled with helium instead of air then we find out velocity of sound in the helium. here velocity of sound in the helium for 0°C is 965m/s
formula for velocity of sound in the helium :
Vw he=Vw at 0°C×√T/273
Whereas Vw he=965×√273+37/273
Vw he=1028m/s
Here we find frequency so fundamental freq=fundamental harmonic no 1(velocity/4(length of tube)
=1(1028/4×0.24)
f=1.07×10³Hz
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The density of a material is a/an ___________.
a) chemical property
b) extensive property eliminate
c) intensive property
d) reactive property
The density of a material is an intensive property.
What is intensive property?
An intensive property of matter is one that does not change with the amount of matter. It is a bulk property, which means that it is a physical property that is independent of sample size or mass. An extensive property, on the other hand, is one that is affected by sample size.
What factors influence an intensive property?Intensive properties are those that are determined solely by the characteristics of the material and not by its quantity - for example, density, temperature, refractive index, color, and pressure. Intensive properties are not additive, which means their value does not change when the amount of material is changed.
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Give an example of a pair of isotopes of the same element. Explain how they are similar and how they are different.
Please help, no bots!
An example of a pair of isotopes of the same element is Hydrogen and Deuterium. They are similar because they have same atomic number and they are different because they have different mass number.
What is Hydrogen ?Hydrogen is a chemical element with the atomic number 1. It is represented with symbol H. Mass number of hydrogen is 1. Hydrogen belong to group 1. It belongs to period 1. Hydrogen is s-block element.
What is Deuterium ?Deuterium is isotope of hydrogen. The atomic of deuterium is 1. The mass number of deuterium is 2. It is also known as heavy hydrogen. It is represented as D or 2H.
Thus from the above conclusion we can say that a pair of isotopes of the same element is Hydrogen and Deuterium.
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What multiplicity would you expect in a 1h nmr spectrum for the indicated proton(s)? (1 pts)
Triplet multiplicity would expect in a 1h NMR spectrum for the indicated proton(s).
The spectrum is the invisible radio frequencies that radio signals pass through. These signals let you make phone calls from your mobile device, tag your friends on call an Uber, and get directions to your destination, all from your mobile device.
Spectrum management is the art and science of managing the use of the radio spectrum to minimize interference and ensure that the radio spectrum is used in the most efficient manner possible for the public good. For USDOT, this focuses on supporting safe, efficient, and economical transportation. Spectrum Networks is a suite of news and sports networks owned and operated by Charter Communications, Inc.
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1. To begin, check that this question is shown: The tallest building in the world, the Burj Khalifa
in Dubai, is 0.828 kilometers high. What is the building's height in centimeters? (If this is not
the question you see, click Next until it appears.)
A. What unit is given in the question?
B. What unit is asked for?
Answer:
Explanation:
a. 82,000
b.Metric unit
6. You are asked to calculate the density of an unknown metal block. The mass of the block was measured to be 83.0 g. When the block was placed in a graduated cylinder containing water, the volume of the block was measured as 17.2 mL. Calculate the density of this unknown metal.
Density of the unknown metal is 4.82 g/mL
A substance's density is defined as its mass per unit of volume. Density is most frequently represented by the symbol ρ.The volume and mass of the substance must be known in order to compute density.Given,
mass of block is 83 g
When the block was placed in a graduated cylinder containing water, the volume of the block was 17.2 mL.
we have to find density with the help of these two terms,
As we know,
Density = Mass/volume
therefore,
Density = 83 / 17.2
= 4.82 g/mL
thus, density of unknown metal block is 4.82g/mL
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The reaction of hydrogen (H2) and fluorine (F2) produces hydrofluoric acid (HF). How many grams of HF are produced if 3.00 g of hydrogen react with excess fluorine with a 25 percent yield?
Taking into account definition of percent yield, 15 grams of HF are produced if 3.00 g of hydrogen react with excess fluorine with a 25 percent yield.
Reaction stoichiometryIn first place, the balanced reaction is:
H₂ + F₂ → 2 HF
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
H₂: 1 molesF₂: 1 moleHF: 2 molesThe molar mass of the compounds is:
H₂: 2 g/moleF₂: 38 g/moleHF: 20 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
H₂: 1 mole ×2 g/mole= 2 gramsF₂: 1 mole ×38 g/mole= 38 gramsHF: 2 moles ×20 g/mole= 40 gramsMass of HF formedThe following rule of three can be applied: if by reaction stoichiometry 2 grams of H₂ form 40 grams of HF, 3 grams of H₂ form how much mass of HF?
mass of HF= (3 grams of H₂× 40 grams of HF)÷ 2 grams of H₂
mass of HF= 60 grams
Then, 3.00 g of hydrogen react with excess fluorine and it forms 60 grams of HF.
Percent yieldThe percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.
The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:
percent yield=(actual yield÷ theorical yield)×100%
where the theoretical yield is the maximum amount of product that could be formed from the given amounts of reagents.
Actual yieldIn this case, you know:
percent yield= 25%actual yield= ?theorical yield= 60 gramsReplacing in the definition of percent yields:
25%=(actual yield÷ 60 grams)×100%
Solving:
25%÷100%= actual yield÷ 60 grams
0.25= actual yield÷ 60 grams
0.25× 60 grams= actual yield
15 grams= actual yield
Finally, 15 grams of HF are produced if 3.00 g of hydrogen react with excess fluorine with a 25 percent yield.
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Where corrosion protection is necessary and the conduit is threaded in the field, the threads must be coated with a(n) ______, electrically conductive, corrosion-resistance compound.
Where corrosion protection is vital and the conduit is threaded in the field, the threads must be coated with a(n) Approved electrically conductive, corrosion-resistance compound.
What is corrosion protection?
A corrosion protection method may be a technique used to minimize corrosion such as the application of anti-corrosion coating, cathodic protection, or other methods that make metal resistant to corrosion.
Metal corrosion in most situations is usually slowed, managed, or maybe put to a stop utilizing the right techniques.
What does one mean by corrosion?
Corrosion may be a natural process which converts refined metal to their more stable oxide.It is the gradual destruction of materials {usually metals} by chemical reaction with their environment.In the most common use of the world, this suggests electrochemical oxidation of metals in reaction with an oxidant such as oxygen.
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A solution is made by dissolving 4.92 g of glucose (c6h12o6) in to 165 ml of water. the molality of this solution is ________ m, if the density of water is 1.00 g/ml.
The molality of this solution is 0.165 m.
m(glucose) = 4.92 grams; mass of glucose
V(water) = 165.0 mL; volume of water
d(water) = 1.00 g/mL; the density of water
M(glucose) = 180 g/mol; molar mass of glucose
n(glucose) = m(glucose) / M(glucose)
moles of glucose = mass of glucose / Molar mass of glucose
n(glucose) = 4.92 g / 180 g/mol
n(glucose) = 0.027 mol
m(water) = 1.00 g/mL x 165 mL
m(water) = 165 g = 0.165 kg
molality = number of moles / mass of water
b(solution) = 0.027 mol / 0.165 kg
b(solution) = 0.165 mol/kg; molality of the solution
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What will be the coordinates of B' if the triangle below is reflected across the y-axis? Pre-image Points: A(1.-4) B(2, -1) C(6,-4) A.(-1,2) B.(1,-2) C.(-2,-1) D.(2,1)
The coordinates of B' is (2,1) if the triangle below is reflected across the y-axis .
Hence , option D is correct one .
A reflection is a transformation of the graph of a function over x - axis or the y - axis ( or both ) . The x-coordinate of each point must be negated while reflecting across the Y- axis, but the value must remain unchanged .
Each point in a figure is transformed into a reflection by reflecting it over a line. This reflection translates the ABC triangle (A, B, and C) . The outcome is a brand-new figure known as the picture .
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The type of synapse that occurs between the terminal end of the presynaptic cell and the dendrites of the postsynaptic cell is referred to as which kind of synapse?
Axodendritic type of synapse that occurs between the terminal end of the presynaptic cell and the dendrites of the postsynaptic cell is referred to as which kind of synapse
Synapses are part of the circuits that connect the sensory organs of the peripheral nervous system to the brain. B. People who perceive pain and touch. Synapses connect neurons in the brain to neurons in the rest of the body, and from those neurons to muscles.
A synapse is a small gap between two neurons where nerve impulses are carried by neurotransmitters from the axon of a presynaptic (transmitting) neuron to the dendrites of a postsynaptic (receiving) neuron. It is called the synaptic cleft or synaptic cleft.
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U-235, the isotope of uranium commonly utilized in nuclear power plants, is _____.
U-235 is utilized for fuel for nuclear power plants and the nuclear reactors that run naval ships and submarines
U-238 makes up 99.27% of natural uranium, together with 0.72% of U-235 and 0.005% of U-234. U-235 is the most often used isotope of natural uranium in nuclear power plants, but because it only makes up 0.72% of natural uranium, it must be enriched in order to be used as fuel in these facilities. The U-238 uranium isotope is the most prevalent and the heaviest of the three naturally occurring uranium isotopes. The uranium fuel is put together in a nuclear reactor so that a regulated fission chain reaction may occur. By splitting the U-235 atoms, heat is produced. This heat is then utilized to create steam, which spins a turbine and powers an electricity-generating generator.
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3-hydroxybutanal can exist in equilibrium as a cyclic hemiacetal.true /false
It is false that 3-hydroxybutanal can exist in equilibrium as a cyclic hemiacetal.
Hemiacetal is produced when one molecule of aldehyde and one molecule of alcohol react.
3-hydroxybutanal (see the structure in the picture below) has both carbonyl and hydroxyl group, so it can, theoretically, undergo an intramolecular reaction to form a cyclic hemiacetal in aquatic solution.
Stability of cyclic hemiacetals depends on the size of the ring. Five or six membered rings are generally favored.
If 3-hydroxybutanal form a cyclic hemiacetal, it will have four membered ring, so it will be very unstable. It cannot exist in aquatic solution, while 4-hydroxybutanal can (see the picture below).
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How many h atoms are in 259 g of c12h21o9? molar mass of c12h21o9 = 309.29 g/mol
Number if atoms in 259 g of [tex]C_12H_2_1O_9[/tex] is [tex]5.04*10^{23}[/tex]
We know that according to Avogadro's law , number of atoms in one mole of molecule is [tex]6.022*10^{23}[/tex] .
In given question we have to find number of atoms in 259 g of [tex]C_12H_2_1O_9[/tex]
The molar mass of [tex]C_12H_2_1O_9[/tex] is given that is [tex]309.29 g/mol[/tex]
Therefore total number of moles = [tex]given mass / molar mass[/tex]
Number of moles = [tex]259/309.29[/tex]
=[tex]0.8374[/tex]
Thus, number of atoms in 0.8374 mole of [tex]C_12H_2_1O_9[/tex] is given by
= [tex]0.8374 * 6.022 * 10^{23}[/tex]
= [tex]5.04*10^{23}[/tex]
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How many molecules of pyruvic acid are produced when a single glucose molecule undergoes glycolysis?.
2 molecules of three carbon pyruvic acid is formed from one molecule of glucose (6-carbon) at the end of glycolysis. There is a net gain of 8 ATP molecules as a result of glycolysis.
Glycolysis is a cytoplasmic pathway which breaks down glucose into two three-carbon compounds and generates energy. Glucose is trapped through phosphorylation, with the assist of the enzyme hexokinase. Adenosine triphosphate (ATP) is used in this reaction and the product, glucose-6-P, inhibits hexokinase.
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Calculate the ratio (lb-mole o2 react/lb-mole no formed). if ammonia is fed to a continuous reactor at a rate of 100.0 kmol nh3/h, what oxygen feed rate (kmol/h) would correspond to 40.0xcess o2?
if ammonia is fed to a continuous reactor at a rate of 100.0 kmol nh3/h
175 Kmol/h is oxygen the fed rate that corresponds to 40% excess O₂.
Given chemical reaction is
4NH₃ + 5O₂ → 4NO + 6H₂O
The molecular weight of NH₃ is 17.03, O₂ is 32, NO is 30, and, H₂O is 18.
To find the ratio,
Ratio = lb-mole O₂ react / lb-mole NO formed
Or, ratio = 5/4
Or, ratio = 1.25
NH₃ fed rate = 100 Kmol/h
We have to find out whether the Oxygen fed rate corresponds to 40% excess O₂.
For each 4 Kmol of NH₃, 5 Kmol of O₂ is required.
4 Kmol of NH₃ ≡ 5 Kmol of O₂
100 Kmol of NH₃ ≡ 125 Kmol of O₂
So, 125 Kmol of O₂ is required for 100 Kmol of NH₃.
For 40% excess of O₂, the required Kmol is = 125 + 125 × 40%
The required Kmol of oxygen is 175 Kmol/h for excess of O₂.
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The distance between the two hydrogen atoms in a molecule of water is 0.000000000172 m. express this distance in scientific notation.
The distance between the two hydrogen atoms in a molecule of water is 0.000000000172 m,1.72x10 ^-10m is the distance in scientific notation.
Distance is the overall movement of an object, regardless of direction. The distance can be defined as the amount of ground an object has moved, regardless of its start or end point. An object's distance can be defined as the complete distance an object travels. for example. If the car drives 5 km east and then turns 8 km north, the total distance traveled by car is 13 km.
Distance is defined as the distance, or separation, between two objects. An example distance is 5 feet between two tables. An example of distance is the difference between both sides of the problem. noun.
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When an acid is dissolved in water, how does it change the solution's ph?
When an acid is dissolved in water, by releasing protons into the solution, it lowers the pH.
What is pH?
The letters pH stand for the potential of hydrogen since pH is essentially a measurement of the number of hydrogen ions (i.e. protons) in a substance. The pH scale was created in 1923 by scientist Peter Lauritz Srensen. (1868-1969).
The pH of a solution is a key marker of its chemical makeup. The pH can have an impact on the biological processes that take place, the behavior of bacteria, and the behavior of chemicals.
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100 ml of a 0.1 mm buffer solution made from acetic acid and sodium acetate with ph 5.0 is diluted to 1 l. what is the ph of the diluted solution?
The pH of the diluted solution is 5.53.
Henderson–Hasselbalch equation for buffer solution:
pH = pKa + log(c(CH₃COO⁻)/c(CH₃COOH))
pH = 5.0 ⇒ c(H⁺) = 10⁻⁵ M
pKa = 4.75 ⇒ Ka = 1.78×10⁻⁵
log(cs/ck) = 5.0 - 4.75 = 0.25
c(CH₃COO⁻)/c(CH₃COO⁻) = 10∧(0.25) = 1.778
c(CH₃COO⁻) + c(CH₃COOH) = 0.1 mM
c(CH₃COO⁻) + c(CH₃COOH) = 1 × 10⁻⁴M
c(CH₃COOH) = 3.6x10⁻⁵ M; concentration of acetic acid before dilution
c(CH₃COOH) = 3.6x10⁻⁶ M; concentration of acetic acid after 10 times dilution
c(CH₃COO⁻) = 6.4x10⁻⁵ M; concentration of sodium acetate before dilution
c(CH₃COO⁻) = 6.4x10⁻⁶ M; concentration of sodium acetate after dilution
c(H⁺) = 10⁻⁶ M; concentration of hydrogen ions
After buffer solution is diluted to 1 l:
Ka = (c(CH₃COO⁻) + x) × (c(H⁺) + x) / (c(CH₃COOH) - x)
1.78×10⁻⁵ = (6.4x10⁻⁶ M + x) × (10⁻⁶ M + x) / (3.6x10⁻⁶ M - x)
x = 2.12×10⁻⁶ M
c(H⁺) = 10⁻⁶ M + 2.12×10⁻⁶ M
c(H⁺) = 3.12×10⁻⁶ M
pH = -logc(H⁺)
pH = -log3.12×10⁻⁶ M
pH = 5.53
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true or false: sn2 mechanism for nucleophilic substitution reactions involves one step and occurs with inversion of configuration.
Sn2 mechanism for nucleophilic substitution reactions involves one step and occurs with inversion of configuration is true.
Sn2 is a single-step mechanism in which the bond is broken by the attacking nucleophile from the back of the carbon atom. Two reactants are involved in this reaction.
In this mechanism, The nucleophile approaches the substrate at 180° to the carbon leaving group. The carbon-nucleophile bond is formed and the carbon leaving group breaks.
The nucleophile can attack at the same side where the leaving group is present or the nucleophile can attack from the opposite side of the carbon atom. Since complete inversion of configuration is required, so it is compulsory for the nucleophile to attach from the opposite side.
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How many ions of Na+ and C1- will be present in 30g of NaCl?
Ans fast plis
3.08*10^23 ions of Na+ and Cl- will be present in 30g of NaCl.
Weight of NaCl is equal to sum of weight of one mole of sodium and one mole of chloride.
Mathematically, it can be represented as -
1 mol (Na) + 1 mol (Cl)
= 23.0+ 35.5
= 58.5 g/mol
In 58.5 gram of NaCl, there is one mole of Na or 6.02*10^23 ions
In one gram of NaCl, there will be
=6.02*10^23/58.5 sodium ions
In 30 grams of NaCl, the number of sodium ions will be -
(6.02*10^23*30)/ 58.5
=3.08*10^23 ions
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If a capacitor is overcharged, the electrons from the negative plate could be pulled through the insulation to the positive plate. the capacitor is said to be ? .
If a capacitor is overcharged, the electrons from the terrible plate may be pulled through the insulation to the high-quality plate. the capacitor is stated to be shorted.
Overcharging could only mean exceeding its voltage rating.The capacitor can break down (internally short between terminals) overheat and or open circuit. Some capacitors can literally ooze chemicals or “pop” or explode and/or catch fire.while you join a capacitor to DC voltage, the capacitor will price to this voltage, and the charging current will drop to zero.
You need to make certain the voltage isn't better than the capacitor’s Shorting.
On AC, the capacitor will comply with the voltage, w/a put off. again, you need to make sure the voltage rating of the capacitor fits the voltage(In this situation peak voltage).
If the voltage is higher in either case-the capacitor may short.
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What mass of agcl will precipitate when 10.0 g of nacl is added to an aqueous solution of agno3?
When 10.0 g of NaCl is added to an aqueous solution of AgNO₃, 24.5 g AgCl will be precipitated.
The balanced chemical reaction is:
NaCl(aq) + AgNO₃(aq) → AgCl(s) + NaNO₃(aq)
Molar mass of NaCl = 58.5 g
Molar mass of AgCl = 143.5 g
Number of moles of NaCl = Given Mass
Molecular Mass
= 10.0 g ÷ 58.44 g/mol
= 0.171 moles
From the reaction,
58.5 g of NaCl produces 143.5 g of AgCl
10.0 g of NaCl will produce 143.5 × 10.0 = 24.5 g AgCl
58.5
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What type of functional groups or atoms would need to be present in the r groups for hydrogen?
Alcohols (O-H), acids (COOH), or amines (NH2)-polar groups are need to be present in the R group for hydrogen.
This type of functional group contains only hydrogen and carbon as constituent elements. They are commonly represented with ‘R’. They are also called hydrocarbyl groups. The bonding between the carbon atoms can be single, double, or triple.
When we define a functional group, we imply a group of atoms of the same or different elements forming a chemically-active section of a compound and creating a class of new compounds. In organic chemistry, there are many such functional groups. For example, an alcohol group (-OH) defines a particular set of characteristics of the compounds that have it as a constituent. These characteristics will vary from one functional group to the other.
Therefore,
Three function groups Alcohols (O-H), acids (COOH), or amines (NH2) needs to be present in the R group for hydrogen.
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Which has the greatest number of hydrogen atoms? group of answer choices 1020 hydrogen atoms 100 g of a substance that is 2% h by mass 100 g of water 20 g of hydrogen gas
20gm of hydrogen will have highest number of hydrogen atoms.
We know that 1 mole of substance contains atoms equal to Avogadro number i.e. [tex]6.022*10^{23}[/tex]
As molar mass of hydrogen is 1gm there 1 mole of hydrogen contains 1gm of hydrogen and [tex]6.022*10^{23}[/tex] hydrogen atoms
If we take 1020 hydrogen atoms then it is very less than [tex]6.022*10^{23}[/tex] hydrogen atoms.
In 100gm of substance if hydrogen is 2% by mass i.e. we have 2gm of hydrogen atom which means 2 mole of hydrogen atoms
Mass of 1 mole of water is 18gm
Thus 100 gm of water have 5.55 moles of water
In 1 mole of water we have 2 grams of hydrogen
Therefore 5.55 moles of water contains 11.11gm of water i.e. 11.11 mole of water
11.11gm of water = [tex]11.11* 6.022 * 10^{23}[/tex] atoms
In 20gm of hydrogen we have 20 mole of hydrogen
i.e. [tex]20* 6.022 * 10^{23}[/tex]
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B. how much of a 5.0 m naoh solution do you need to add to raise the ph to 6.09?
There are 0.037 NaOH will be needed to raise the pH 6.09.
Henderson equation, convey the pH of a buffer solution as a purpose of the concentration of the weak acid or base and the salt constituents of the buffer.
Formula of Henderson equation
pH = pKa + log10 ([A] / [HA])
Basic buffer has a basic pH and is get ready by blend a weak base and its salt with powerful acid.
According to Henderson equation pH of basic buffer is:
pH + pNaOH = 5.0
6.09 + pNaOH = 5.0
pNaOH = 5.0 - 6.09
pNaOH = log(1.09)
pNaOH = 0.037
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What will happen to the potency of acetylcholine after replacing the acetyl group with propionyl or butyryl groups?
The potency of acetylcholine after replacing the acetyl group with propionyl or butyrly group decreases.
Its is a organic chemical that function in the brain and body fofmany types of animal ,and humans also as neurotransmitter.
It act as a messenger , that plays a very important role in the central and peripheral nervous system.
The acetylcholine is important for autonomic body functions, muscle control and memory , learning and attention.
Lack of acetycholine cause no contraction in muscles.
Excess of acetylcholine causes cramps , muscular weakness blurry vision, diarrhea etc.
Propionyl or butyryl is higher homologus group than acetyl , this is the reason the potency will decreases or reduces its activity.
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Explain how the variation in carbon skeleton contributes to diversity and complexity of organic molecules?
Carbon skeletons may vary in shape, length, number, location and strenght of covalent bonds between carbon atoms.
Element carbon is in group 14 of Periodic table of elements.
Electron configuration for carbon: ₆C 1s² 2s² 2p².
Valence electrons are in 2s and 2p orbitals. There is one pair of electrons in 2s orbital and two lone electrons in 2p orbital with the same electron spin.
A carbon atom has four covalent bonds with other carbon atoms in an organic compound.
Carbon also has different type of hybridization (sp, sp2 and sp3).
The strenght of carbon-carbon bond is approximately 350 kJ/mol.
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