Answer:
154.61 g.
Explanation:
he balanced chemical equation for the reaction of KCIO3 to form KCl and O2 is:
2KCIO3 -> 2KCl + 3O2
From this equation, we can see that for every 1 mole of KCIO3, 2 moles of KCl and 3 moles of O2 are produced.
First, we need to calculate the number of moles of KCIO3:
n = mass / molar mass
= 125g / (138.2 g/mol)
= 0.902 moles
Now that we have the number of moles of KCIO3, we can calculate the masses of the products:
Mass of KCl = 0.902 moles * (74.55 g/mol) = 67.53 g
Mass of O2 = 0.902 moles * (32.00 g/mol) * 3 = 87.08 g
So the total mass of the products will be:
67.53 g + 87.08 g = 154.61 g.
ALLEN
cone balanced on its small end is in stable equilibrium. negative equilibrium. unstable equilibrium. neutral equilibrium. positive equilibrium.
A balanced cone on its small end is in inconsistent equilibrium. Equilibrium refers to a state of balance where an object isn't accelerating or changing its stir.
An object can be in one of three types of equilibrium stable, neutral, or unstable. In stable equilibrium, an object that's displaced from its position will witness a restoring force that brings it back to its original position. For illustration, a ball at the bottom of a coliseum is in stable equilibrium because if it's displaced from its position, graveness will beget it to roll back to the bottom of the coliseum. In neutral equilibrium, an object that's displaced from its position will remain in its new position. For illustration, a ball balanced at the top of a hill is in neutral equilibrium because if it's displaced from its position, it'll remain at its new position and not roll back to the top of the hill. In unstable equilibrium, an object that's displaced from its position will witness a force that will move it further down from its original position. For illustration, a cone balanced on its small end is in unstable equilibrium because if it's displaced from its position, it'll fall over and move further down from its original position. thus, a cone balanced on its small end is in unstable equilibrium.
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A cone balanced on its small end is in stable equilibrium. In stable equilibrium, an object is in a balanced state where any slight disturbance will cause the object to return to its original position.
This is because the center of gravity of the cone is located directly above its base, creating a low center of gravity.
To understand this concept, imagine a cone standing on its small end. The base of the cone provides a wide and stable support. The center of gravity, which is the point where the weight of the cone is concentrated, is located directly above the base. This means that any slight tilt or disturbance to the cone will result in the center of gravity moving to a lower position, causing the cone to return to its original upright position.
In contrast, if the cone were balanced on its large end, it would be in an unstable equilibrium. In this case, the center of gravity is located above the narrow top of the cone, making it easy for the cone to topple over with even a slight disturbance. This is because the center of gravity is higher than the base, making the cone top-heavy.
Therefore, a cone balanced on its small end is an example of stable equilibrium.
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assuming all of these molecules have the same number of carbon atoms, which functional group would have the highest boiling point?
The correct answer is
Aldehyde would have the highest boiling point
Aldehydes and ketone both include a carbonyl group. Aldehydes are thought to be the most important functional group. They go by the labels formyl or methanoyl group. Aldehydes get their name from the dehydration of alcohols. Aldehydes have a carbonyl group attached to at least one hydrogen atom. In ketones, the carbonyl group is joined to two carbon atoms.
Examples of organic compounds with the carbonyl functional group, or C=O, include aldehydes and ketones. The carbon atom of this group has two empty bonds that may be filled with hydrogen, an alkyl group, or an aryl group. If at least one of these substituents is hydrogen, the compound is an aldehyde. If none of these contains hydrogen, the material is a ketone.
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what happens to the stereochemistry of a chiral alcohol when converted to an alkyl bromide with pbr3?
The alcohol is converted into a good leaving group during the "activation" step by forming an O-P bond and displacing Br from P [note that this is essentially nucleophilic substitution at phosphorus].
With phosphorus tribromide (PBr3) or thionyl chloride, alcohols can be converted into alkyl halides (SOCl2).
The reaction with PBr3 involves a configuration inversion at carbon.
The reaction with SOCl2 also occurs with configuration inversion [but check with your instructor to see if the SNi mechanism is covered].
Because it avoids the possibility of carbocation rearrangements, using PBr3 and SOCl2 to convert alcohols to alkyl halides is much more mild and predictable than using HBr or HCl.
PBr3's most important reaction is with alcohols, where it replaces an OH group with a bromine atom to form alkyl bromide.
The nucleophilic substitution reaction occurs when alcohol reacts with phosphorous tribromide, resulting in the formation of alkyl bromide.
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