A certain rifle bullet has a mass of 6.93 g. Calculate the de Broglie wavelength of the bullet traveling at 1649 miles per hour.

Answers

Answer 1

The de Broglie wavelength of the bullet traveling at 1649 miles per hour is  1.3 x 10^34 m.

What is de Broglie wavelength?

The  wavelength that is associated with an object in relation to its quantum and mass is known as de Broglie wavelength.

The particles de Broglie wavelength is inversely proportional to its force.

de Broglie wavelength is expressed as : ^ = h/mv

Where ^ is wavelength, h is plank constant, m is mass and v is velocity.

1 miles = 1.60934 km

So  1649 miles = 2653.8 km

Then 2653.8 x 1000/ 60x60 = 737.2 ms -1.

The momentum  of bullet is p = mv = 0.00693kg x 737.2 ms-1

                                                          = 5.109 kg/ms

Now, de Broglie wavelength = h/p = 6.63 x 10^-34 / 5.109 kg/ms

                                                           =  1.3 x 10^34 m

Thus, de Broglie wavelength of the bullet traveling at 1649 miles per hour is  1.3 x 10^34 m.

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Related Questions

100 Points!

A student reacted 0.3000 grams of aluminum with oxygen gas and obtained 0.5333 grams of aluminum oxide. Based upon the experimental data, determine the experimental empirical formula of this aluminum oxide.

Answers

Answer:

Empirical Formula = Al3O4 .

Explanation:

Mass of Aluminium = 0.3000 g

Mass of Oxygen in oxide = 0.5333 g - 0.3000 g = 0.2333 g

Moles of Aluminium = Mass / MOlar Mass = 0.3000 g / 27 g = 0.01112 moles

Moles of Oxygen = Mass / Molar Mass =0.2333 g / 16 g = 0.01458 moles

Now we will divide each of the molar quantities by the smallest number of moles.

Aluminium : 0.01112 moles / 0.01112 moles = 1

Oxygen : 0.01458 moles/ 0.01112 moles =1.31

Since, the ratio between Al and O is 1:1.31 which is not the smallest whole numebr ratio. SO, we will multiply it by the smallest number to get whole number ratios.

So, Here on multiplying the ratio by 3 ,we get Al : O = 3:4.

The experimental empirical formula of the aluminum oxide is Al₂O₃.

To determine the empirical formula of the aluminum oxide, we need to calculate the mole ratios of aluminum (Al) and oxygen (O) based on the given masses.

Convert the masses of aluminum and aluminum oxide to moles:

Aluminum: 0.3000 grams Al * (1 mole Al / molar mass of Al) = X moles AlAluminum oxide: 0.5333 grams Al₂O₃ * (1 mole Al₂O₃ / molar mass of Al₂O₃) = Y moles Al₂O₃

Determine the mole ratio of Al to Al₂O₃:

Divide the number of moles of Al by the number of moles of Al₂O₃: X moles Al / Y moles Al₂O₃ = Z

Simplify the mole ratio to obtain the empirical formula:

If Z is close to a whole number or a simple ratio (e.g., 1:1, 2:1, 3:1), we can assume the empirical formula is Al₂O₃. In this case, we have assumed that the experimental data is consistent with the empirical formula Al₂O₃.

It is important to note that the given experimental data and the resulting empirical formula are based on the assumption that the reaction went to completion and that the measurements were accurate. Further confirmation and analysis, such as using additional experimental techniques or calculations, may be necessary to verify the empirical formula.

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Can you please help me

Answers

The answer should be A

please answer holy its been an hour

Answers

Reverse the sign of the second equation, change the sign of the enthalpy and add. Option B

What is the enthalpy?

The enthalpy could be obtained by the use of the Hess law of constant heat summation. As such, we have a number steps and it is possible for use to obtain the enthalpy of the final reaction as shown by a series of manipulations.

By inspection, we can see that, if we desire to obtain the enthalpy of the final reaction as shown, then we have to reverse the sign of the second equation, change the sign of the enthalpy and add. Option B

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How does she/Judy Hopps discover Nick Wolf’s true intentions/con in the movie Zootopia?

Answers

Answer:

I think it was when she caught him talking to his "child"

A student creates a scale model of planets where 1 centimeter (cm) is equal to 10,000 kilometers (km). In this model, which planet would have a diameter of approximately 12 cm?

Answers

The planet that would have a diameter of approximately 12 cm is Saturn.

What is a scale model?

A scale model is a model which is used to represent another object using a given scale.

Scale models can be used to make small object bigger or larger objects smaller.

Considering the scale model of the planets where  1 centimeter (cm) is equal to 10,000 kilometers (km);

1 centimeter = 10,000 kilometers

12 centimeter = 1.2 × 10⁵ kilometers

The planet with a diameter of approximately 1.2 × 10⁵ kilometers is Saturn.

In conclusion, scale models are used to model objects.

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How many atoms of hydrogen are in 3 moles of ammonia, NH3?

Answers

Answer:

[tex]5.4198[/tex] × [tex]10^{24}[/tex] atoms of hydrogen

Explanation:

Firstly, we need to know how many atoms of [tex]NH_{3}[/tex] are there in 3 moles of [tex]NH_{3}[/tex].

We know that there is [tex]6.022[/tex] × [tex]10^{23}[/tex] atoms in a mole of any substance.

[tex]6.022[/tex] × [tex]10^{23}[/tex] is Avogadro's Constant

[tex]6.022[/tex] × [tex]10^{23}[/tex] × 3 =  [tex]1.8066[/tex] × [tex]10^{24}[/tex]

Therefore in 3 moles of ammonia, there are [tex]1.8066[/tex] × [tex]10^{24}[/tex] atoms.

Next, you should determine how many molecules of an element is present in ammonia.

There is 1 Nitrogen molecule and 3 Hydrogen molecules for every mole of ammonia.

Finally, since we know 3 moles of ammonia contains [tex]1.8066[/tex] × [tex]10^{24}[/tex] atoms, we just have to multiply accordingly to get the individual amount of atoms of an element a compound has.

For Nitrogen :

1 × [tex]1.8066[/tex] × [tex]10^{24}[/tex] =  [tex]1.8066[/tex] × [tex]10^{24}[/tex] atoms of nitrogen

For Hydrogen :

3 ×  [tex]1.8066[/tex] × [tex]10^{24}[/tex] =  [tex]5.4198[/tex] × [tex]10^{24}[/tex] atoms of hydrogen

Therefore, there is [tex]5.4198[/tex] × [tex]10^{24}[/tex] hydrogen atoms in 3 moles of ammonia.

Hope this answer helped!

(01.07 LC)
Emma used an equal arm balance to weigh a 1.134 g sample of calcium carbonate. Which of these
measurements made by Emma is the most accurate? (5 points)
Select one:
O
a.1.1 g
b.1.2 g
c.1.3 g
d.1.4 g
(01.07 MC)
Look at the two thermometers.
D

Answers

The most accurate measurement is 1.1 g. Option A

What is accuracy?

The term accuracy refers to the fact that the measurement is close to the true value. The closer the measurement is to the true value as given, the more accurate it is.

In this case, the true value of the mass of the  sample of calcium carbonate is 1.134 g. Now we have to look at all the masses of as obtained by Emma during the experiment.

The most accurate measurement is 1.1 g. Option A

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The accepted value for the density of iron is 7.9 g/mL. Four student groups examine the density of iron in the lab. Which of the following experimental results are most precise?

Answers

For 5.43 g/mL and 5.44 g/mL =  0.01 the least diff and most precise.

First of all, precision is determined by the difference in the two obtained values. If the difference between the two values obtained is less, then precision is more. If the difference between the two values obtained is more, then precision is less.

For 5.43 g/mL and 5.44 g/mL , we can see that the difference between these two data is 0.01

For 7.98 g/mL and 7.91 g/mL , we can see that the difference between these two data is 0.07

For 7.65 g/mL and 7.64 g/mL , we can see that the difference between these two data is 0.01

For 7.06 g/mL and 7.03 g/mL , we can see that the difference between these two data is 0.03

As we can see that, the most difference between the data is 0.07 between 7.65 g/mL and 7.64 g/mL and thus, they are least precise.

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ASAP HELP

When one molecule of sucrose is burned with oxygen to make carbon dioxide and water, how
many carbon dioxides are made? Hint, carbon dioxide is CO2.
6 12 1 24

Answers

One molecule of sucrose is burned with oxygen to make carbon dioxide and water.

Disaccharide sugar sucrose is composed of glucose and fructose. It is produced naturally by plants and is the main component of white sugar. C₁₂H₂₂O₁₁ is the chemical formula for it.

Extraction and refining sucrose for human use can be done from either sugarcane or sugar beet. Raw sugar is created from crushing the cane, which is consistently delivered to other sectors to be refined into pure sucrose. Sugar mills generally are located in the tropical regions near the sugarcane plantations.

                   C₁₂H₂₂O₁₁ + 12O₂  →  12CO₂ + 11H₂O

When one molecule of sucrose is burnt, we get 12 carbon dioxide molecules.

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A 1.50 gram sample of contain 3.32g of CO2 1.58g of N2O5 and 1.865g of H2O .Its molar mass is 102.2g/mol. Determine the emperical and molecular formulas.

Answers

The correct answer for emperical and molecular formula = C5H14N2 .

3.23 g x (12.011 / 44.0098) = 0.8815 g carbon

1.865 g x (2.016 / 18.0152) = 0.2087 g Hydrogen

1.58 g x (28.014 / 108.009) = 0.4098 g Nitrogen

1.50 g minus (0.8815 + 0.2087 + 0.4098) = 0.

Convert each element's mass to moles.

0.8815 g/12.011 g/mol = 0.0734 mol carbon

0.2087 g 1.008 g/mol = 0.207 mol Hydrogen

0.4098 g 14.007 g/mol = 0.02926 mol Nitrogen

Step three is to calculate the ratio of molar amounts expressed in the smallest, whole numbers.

0.0734 mol 0.02926 mol = 2.51 carbon

7.07 mol hydrogen = 0.207 mol 0.02926 mol

Nitrogen: 0.02926 mol = 1 Nitrogen: 0.02926 mol = 1

Doubling each value yields C = 5, H = 14.14, and N = 2, resulting in the empirical formula C5H14N2

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What is the limiting reactant if 0.5 g Al is reacted with 0.5 g CuCl2?
What is the theoretical yield of copper produced by this reaction?

Answers

1. The limiting reactant is CuCl₂

2. The theoretical yield of copper is 0.24 g

Balanced equation

2Al + 3CuCl₂ —> 2AlCl₃ + 3Cu

The following were obtained from the balanced equation:

Molar mass of Al = 27 g/mol Mass of Al from the balanced equation = 2 × 27 = 54 gMolar mass of CuCl₂ = 63.55 + (2 × 35.5) = 134.55 g/mol Mass of CuCl₂ from the balanced equation = 3 × 134.55 = 403.65 gMolar mass of Cu = 63.55 g/mol Mass of Cu from the balanced equation = 3 × 63.55 = 190.65 g

From the balanced equation above,

54 g of Al reacted with 403.65 g of CuCl₂ to produce 190.65 g of Cu

1. How to determine the limiting reactant

From the balanced equation above,

54 g of Al reacted with 403.65 g of CuCl₂

Therefore,

0.5 g of Al will react with = (0.5 × 403.65) / 54 = 3.74 g of CuCl₂

From the above calculation, we can see that a higher amount (i.e 3.74 g) of CuCl₂ than what was given (i.e 0.5 g) is needed to react completely with 0.5 g of Al.

Thus, CuCl₂ is the limiting reactant.

2. How to determine the theoretical yield of copper

From the balanced equation above,

403.65 g of CuCl₂ reacted to produce 190.65 g of Cu

Therefore,

0.5 g of CuCl₂ will react to produce = (0.5 × 190.65) / 403.65 = 0.24 g of Cu

Thus, the theoretical yield of Cu is 0.24 g

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Which of the following best describes the reaction seen below?

2H2(g) + O2(g) → 2H2O(l)

a.
Two grams of hydrogen gas combine with 1 gram of oxygen gas to form 2 grams of water.

b.
Two molecules of hydrogen gas combine with 1 molecule of oxygen gas to form 2 molecules of water.

c.
Two liters of hydrogen gas combine with 2 liters of oxygen gas to form 2 liters of water.

d.
Two hydrogen atoms combine with 1 oxygen atom to form 2 water molecules.

Answers

Two molecules of hydrogen gas combine with 1 molecule of oxygen gas to form 2 molecules of water.

What is a word equation?

A word equation is one in which the equation that is shown in the reaction is written in words rather than by the use of the chemical symbols of the elements that are involved.

We have the reaction; [tex]2H_{2} (g) + O_{2} (g) ---- > 2H_{2} O(l)[/tex], in order for this reaction to be written in the word equation form we have; Two molecules of hydrogen gas combine with 1 molecule of oxygen gas to form 2 molecules of water.

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The molecular weight of urea ((NH2)2CO), a compound used as a nitrogen fertilizer, is ________ amu (rounded to one decimal place).

Answers

The molecular weight of  urea [tex]((NH_{2} )_{2} CO)[/tex] , a compound used as a nitrogen fertilizer, is 60 amu .

We may determine the atomic weights of the elements using their periodic tables, and we discover that hydrogen has an atomic weight of 1, while that of oxygen is 16. We sum the contributions from each atom to determine the molecular weight of one water molecule, which is 2(1) + 1(16) = 18 grams/mole.

The molecular weight of urea [tex]((NH_{2} )_{2} CO)[/tex] is calculated as ,

The atomic weight of carbon ( C ) = 12

The atomic weight of nitrogen ( N ) = 14

The atomic weight of oxygen ( O ) = 16

The atomic weight of hydrogen ( H ) = 1

[tex]((NH_{2} )_{2} CO)[/tex] = 2 × ( 14 + 2 ) + 12 + 16 = 60 g / mole .

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How do i solve. To get the answer need answer

Answers

The correct answer is 329.4 Cal.

Remember that specific heat is the ratio of the amount of heat needed to raise a body's temperature by one degree compared to the amount of heat needed to raise the temperature of an equivalent mass of water by one degree, or that specific heat capacity is the amount of heat energy needed to raise a material's temperature by one kelvin (K) per kilogramme.

Mass of sample=50.00-g

Specific heat of metal=0.108 cal/g °C

Change in temperature=78.0 °C-17.0°C=61.0°C

Heat Released by metal can be calculated as follows:

Heat Released = Mass of sample  x Specific heat x  Change in temperature

Heat Released = 50.00 g x  0.108 cal/g °C x 61.0°C

Heat Released = 329.4 Cal

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if the statue has a volume of 4.9m^3 and the density of marble is 2.76g/cm^3 what is the mass of the statue

Answers

If the statue has a volume of 4.9m^3 and the density of marble is 2.76g/cm^3 then, the mass of the statue is 0.563 kg.

Equation :

ρ = m / V

where,

ρ =  density

m = mass

V = volume

As given in the equation,

ρ is 2.76g / cm³

V is 4.9m³

So by using the formula,

ρ = m / V

we have,

2.76g / cm³ = m / 4.9m³

m = 2.76 / 4.9

m = 0.563 kg

Volume :

Volume is a measurement of the amount of three-dimensional space that is occupied. It is frequently numerical quantified using SI-derived units or various imperial units. The definition of length is linked to the definition of volume. In contrast, the mass and density formula is rho = m / V.

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why is unauthorized modification of car is dangerous? ​

Answers

Answer:

It is dangerous because it can be harder to drive the car.

Explanation:

Any alterations in your car can void some of your warranties and may also pose some safety concerns. It is also illegal as well.

Which one is more basic, Li2O or Na2O? why?

Answers

Answer:

Na2O is more basic. The reasoning for this is because the basis of periodicity going from bottom to lower basicity is increase.

What are the characteristics of a metallic bond?
A. Electrons are shared unequally between two atoms.
B. Electrons move freely among positively charged ions.
C. Electrons are shared equally between two atoms.
OD. Electrons are transferred from one atom to another.

Answers

Answer: my answer would be a

Explanation: so i did some research and all of it came up with the answer (A).

D) Chemical, Reactivity
Physical or Chemical Change? Why? Iron reacts with Sulphur to give heat and a flame.
(A) Chemical, Smell/Taste
B) Chemical, Color/Sight
c) Chemical, Combustibility/Reaction
D) Physical, Color

Answers

c) Chemical, Combustibility/Reaction Iron reacts with Sulphur to give heat and a flame.

What happens when you heat iron and sulphur together?

Iron sulphide, a chemical, is created when you burn iron and sulphur together. A series of chemical compounds comprised of iron and sulphur is referred to as iron sulphide, or simply iron sulphide. The chemical molecule and mineral known as iron sulphide, sometimes known as iron(II) sulphide, has the formula FeS.

Incandescence is the process of a solid emitting light after being heated till it glows or emits light. The colour of an iron bar when warmed to a very great temperature changes from red to white as the temperature increases.

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Calculate the areas and densities. Report the answers in the correct units.

a. the area of a rectangle with sides measuring 3 x 10^1 cm and 3 x 10^-2 cm

b. the area of a rectangle with sides measuring 1 x 10^3 cm and 5 x 10^-1 cm

c. the density of a substance having a mass of 9 x 10^5 g and a volume of 3 x 10^-1 cm3

d. the density of a substance having a mass of 4 x 10^-3 g and a volume of 2 x 10^-2 cm3

Answers

Considering the defintion of area of a rectangle and definition of density, you obtain the following areas and densities:

a. the area of the rectangle is 9×10⁻¹ cm².

b. the area of the rectangle is 5×10⁻²cm².

c. the density of the substance is 3×10⁶ g/cm³.

d. the density of the substance is 0.2 g/cm³.

Area of a rectangle

A rectangle is a flat geometric figure with four sides, of which two sides that are opposite parallel to each other have the same length and the remaining two have another length.

The area of a rectangle is the product of the two contiguous sides of the rectangle:

Area of a rectangle= a×b

where a and b are the measures of the two sides.

Definition of density

Density  is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

The expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density= mass÷ volume

a. Area of the rectangle

In this case, you know that the rectangle has:

a side of the rectangle is 3×10¹ cm.a side of the rectangle is 3×10⁻² cm.

Then, the area of the rectangle can be calculated as:

Area of the rectangle= 3×10¹ cm× 3×10⁻² cm

To multiply numbers in scientific notation, you multiply the numbers that are not powers of 10 and add the exponents that are powers of ten. In this case:

Area of the rectangle= (3× 3)×10¹⁻² cm²

Area of the rectangle= 9×10⁻¹ cm²

Finally, the area of the rectangle is 9×10⁻¹ cm².

b. Area of the rectangle

In this case, you know that the rectangle has:

a side of the rectangle is 1×10³ cm.a side of the rectangle is 5×10⁻¹ cm.

Then, the area of the rectangle can be calculated as:

Area of the rectangle= 1×10³ cm× 5×10⁻¹ cm

Solving

Area of the rectangle= (1× 5)×10³⁻¹ cm²

Area of the rectangle= 5×10⁻²cm²

Finally, the area of the rectangle is 5×10⁻²cm².

c. Density of the substance

In this case, you know:

mass= 9×10⁵ gvolume= 3×10⁻¹ cm³

Replacing in the definition of density:

density= 9×10⁵ g÷ 3×10⁻¹ cm³

Solving:

density= 3×10⁶ g/cm³

Finally, the density of the substance is 3×10⁶ g/cm³.

c. Density of the substance

In this case, you know:

mass= 4×10⁻³ gvolume= 2×10⁻² cm³

Replacing in the definition of density:

density= 4×10⁻³ g÷ 2×10⁻² cm³

Solving:

density= 0.2 g/cm³

Finally, the density of the substance is 0.2 g/cm³.

Summary

In summary, you obtain the following areas and densities:

a. the area of the rectangle is 9×10⁻¹ cm².

b. the area of the rectangle is 5×10⁻²cm².

c. the density of the substance is 3×10⁶ g/cm³.

d. the density of the substance is 0.2 g/cm³.

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If 31.5 grams of bromine and 14.0 grams of chlorine combine to form bromine monochloride, how many grams of bromine monochloride must form?

Answers

The correct answer is 45.21 g.

This issue will be resolved with the aid of the idea that chemical equilibrium is the rate of reversible processes at which the concentration of the reactants and products does not vary over time. The rate of reaction is exactly proportional to the raised to the power equal to the relevant stoichiometric coefficient, states the law of mass action.

Bromine monochloride is created when 31.5 grammes of bromine and 14.0 grammes of chlorine react.

Br2 + Cl2 ---> 2BrCl

mol Br2= 31.5/160g/mol= 0.196mol

mol Cl2= 14g/70.906g/mol= 0.197mol

Number of moles of BrCl formed = 2×0.196= 0.392 mol.

mass BrCl= 0.392 mol x 115.357g/mol= 45.21 g

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Ethyl alcohol, also known as ethanol, has a density of 0.79 g/mL. What is the volume, in quarts, of 1.95 kg of this alcohol?
Express your answer using two significant figures.

Answers

Taking into account the definition of density, the volume of 1.95 kg of alcohol is 2.6083 quarts.

Definition of density

Density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

The expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density= mass÷ volume

It can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

Volume in this case

In this case, you know that:

Density= 0.79 g/mLMass= 1.95 kg= 1950 g

Replacing in the definition of density:

0.79 g/mL= 1950 g÷ volume

Solving:

0.79 g/mL ×volume= 1950 g

volume= 1950 g÷ 0.79 g/mL

volume= 2468.35 mL= 2.6083 quarts (being 1 mL= 0.00105669 quarts)

In summary, the volume of 1.95 kg of alcohol is 2.6083 quarts.

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What are FIVE investigation techniques Judy Hopps and Nick Wilde use to crack the case in the movie Zootopia?

Answers

Answer:

1 - Crime Scene Analysis

2 - Conducting Interviews

3 - Surveillance

4 - Interrogation

5 - Developing Other Sources of Information

Explanation:

1 - Judy and Nick investigate the limousine where the attack occurred, discovering polar bear fur.

2 - Judy and Nick interview the elephant Yoga Instructor (really the Yak) at the Mystic Spring Oasis.

3 - Judy and Nick watch Zootopia Traffic Network surveillance in the Assistant Mayor's Office to discover where the "Night Howlers" were going.

4 - Judy interrogates the weasel who stole the onions earlier in the movie with the help of Mr. Big threatening to ice him.

5 - Judy uses leverage to force Nick Wilde to help in the investigation. Nick provides another source of information with his connection to his friend Flash at the Department of Mammal Vehicles who runs their plate number.

*These Investigation Techniques are defined in the study "CRIMINAL INVESTIGATION TECHNIQUES" listed on the U.S. Department of Justice Office of Justice Programs website*

The electronic configuration 1s2,2s2,2p6,3s2 belongs to which element?

Answers

The electronic configuration 1s2,2s2,2p6,3s2  belongs to Magnesium.

Electronic configuration depicts the filling of electrons in the subshell and predicts the properties of the elements.The electronic configuration has two electrons in the outermost shell which depicts the alkaline earth metal group.Checking from the periodic table we get the element as magnesium.The distribution of electrons in an element's atomic orbitals is described by the element's electron configuration. Atomic electron configurations are represented via a common notation in which all atomic subshells that contain electrons (with the number of electrons written in subscript)Uses for electron configurations include: figuring out an element's valency, predicting a set of components' qualities (elements with similar electron configurations tend to exhibit similar properties).It also helps in analyzing atomic spectrum data.

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Which of the following best describes a community?
• A. An interacting group of populations that occupy the same area
© B. A group of organisms that interbreed and have common
characteristics
• C. A group of organisms that interact with nonliving parts of the
environment
• D. All of the individuals of the same species that inhabit an
area

Answers

The following best describes a community

community is best describes as  An interacting group of populations that occupy the same area

individuals of the equal species dwelling together contain a populationA network includes  a doubtlessly interacting populations of different speciespopulation consists of individuals of the same species that live inside the same area, proportion the same habitat and sources, and probably interbreed with each other.A community and the nonliving elements with which it interacts is known as a ecosystemspecies is all of the populations of a particular type of organism.If a populace is experiencing exponential boom, it approach the larger the population, the faster it grows

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a protostaar forms once the nebular cloud condenses and the core begins

Answers

the protostar forms once the nebular cloud condenses and the core begins to hear.

PLS HELP ME WITH MY CHEMISTRY

Answers

Answer:

Explanation:density=mass×volume

so your answer will be 14.7×6.6=97.02

Order these materials from best to worst conductors of heat
Chalk, Air, Iron, stainless steal, copper, concrete, diamond and oak.

Answers

Answer:copper,stainless steel,iron,diamond,oak,calk,air

Explanation:your metlas is your meterials that absorbs most heat'

A rectangular piece of copper, 2.13 cm by 0.79 cm by 1.14 cm, weighs 17.11g. What is the density of the copper?

Answers

The Density of the copper is 8.91 g/cm³.

What is the density of the copper?

The density of a substance is obtained from the ratio of the mass and the volume of the substance.

The formula of density is given below:

Density = mass/volume

The mass of the copper is 17.11 g

The volume of the rectangular piece of copper is calculated as:

volume = length * breath * height

Volume of the rectangular piece of copper = (2.13 * 0.79 * 1.14) cm³

Volume of the rectangular piece of copper = 1.92 cm³

Density of the copper = 17.11 g/1.92 cm³

Density of the copper = 8.91 g/cm³

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How much energy will a sample of aluminum
gain when it is warmed from 306 K to 419 K? The
specific heat capacity of aluminum is 0.897 J/g.K,
and the mass of the sample is 5.00 g.

Answers

The specific heat capacity of a substance, also known as the massic heat capacity or massic heat capacity in thermodynamics, is the heat capacity of a sample of the substance divided by the mass of the sample. So, the energy gain by sample will be 506J

We know that, the heat energy gained will be calculated by the formula,

Q=mcΔT

where,

Q= Heat energy gained

m=mass

c= specific heat capacity

ΔT= Change in temperature

So, Given,

m= 5.00g ,

ΔT= 419K -306K= 113K

c= 0,897J/gK

Q=mcΔT

Q= 5.0×0.897×113

Q= 506J

So, the energy gained by sample of Aluminum will be 506 J when it is warmed from 306 K to 319K , in which temperature difference is 113K

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