The Speed of wind will be 103.5 m/s.
It is stated in the question that a glider is launched into the wind and in 45 seconds it attains the speed of the wind. Also, It is given that it attains a constant acceleration of 2.29m/s² and it starts moving from a state of rest.
We know the relation between velocity, time, and acceleration can be represented by Newton's first equation: v = u + at
where, v = Final velocity, u = Initial velocity, a = Acceleration, and t = Time
In this case, we have to find the final velocity of the glider to know the speed of the wind, and u = 0, a = 2.29m/s², t = 45sec
Putting values in the equation we get :
=> v = 0 + (2.29)*45
=> v = 103.5
Hence, the Speed of wind will be 103.5 m/s
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what do you mean by impulse of a force ?
don't spam-
Answer:
Explanation:
Impulse of a force is defined as the product of the average force and the time interval for which the force acts on the body.
Answer:
The product of the force & the time for which it acts on a body is called impulse of a force.
Chance drives her scooter 7 km north. She stops for lunch and then drives 5 km east. She spends 2 hours total. What her distance? displacement? average speed? average velocity?
We know that the distance is the difference between two points. The distance covered is a scalar quantity hence we can obtain the total speed algebraically. The displacement is a vector quantity hence we must obtain it geometrically.
Total distance = 7 km + 5 km = 12 km
Total displacement = √7^2 + 5^2 = 8.6 km East of North
Average speed = 12 km/ 2 hours = 6 Km/hr
Average velocity = 8.6 km East of North/2 hours = 4.3Km/hr East of North
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What is the speed of the electron when it is 10.0 cm from the +3.00 nC charge?
The speed of the electron when it is 10.0 cm from the +3.00 nC charge is 30×[tex]10^{-2}[/tex] meters per second.
Given :
q=3.00 nC
r=distance=10 c.m
we apply formula
Velocity of electron =qd
=10×[tex]10^{-2}[/tex]×3=30×[tex]10^{-2}[/tex] m/sec
The speed of electricity is determined by what you mean by the term "electricity." This is a broad term that essentially means "all things relating to electric charge." I'll presume we're talking about an electrical charge current moving through a metal wire, like the power cord of a light. Electrical currents passing through metal wires have three different velocities, all of which are physically significant:
The velocity of electron drift.
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Determine the horizontal distance, d in meters, between the waiter and the diner at the time the cork reaches where the diner had previously been sitting.
T=3.12 Sec
Distance d= 9.703m
The distance can refer to a physical length in physics or to an estimate based on other factors in ordinary language (e.g. "two counties over"). It is sometimes used to indicate the distance between two points: display style |AB||AB|. The terms "distance from A to B" and "distance from B to A" are frequently used interchangeably.
It is a generalization of the idea of physical distance. Distance is a non-numerical measurement in psychology and the social sciences; psychological distance refers to how an object feels.
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Raoul and Maria set out walking from their aunt's house. Raoul walks a certain distance straight east and then a certain distance straight north. A crow passing overhead starts from the same point as Raoul, but flies in a straight line. Raoul observes that the crow flies a total distance of 500 m in a direction 35° north of east to reach the same final point as Raoul. Maria starts from the same point as Raoul, but she walks first straight west and then straight south. Her final point is 700 m from the starting point in a direction that is 55° south of west. How far did Raoul walk on the east leg of his trip? How far on the north leg? Similarly, how far did Maria walk on the west leg and how far on the south leg? Express these quantities in terms of displacement vectors and their components, using a coordinate system with the +x axis pointing east and the +y axis pointing north.
Answer:
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a body of mass 7.5kg is moving with the velocity of 1.2, if a force of 15newton is applied to the body calculate its velocity after 2 seconds
The velocity is 5.2 m/s
Force as per the Newton's second law of motion is defined as, for constant mass, mass times the acceleration
F= m x a
where m is the mass of the body in kilograms and a is the acceleration is m/s^2
Now we know that acceleration is nothing but rate of change of velocity
i.e. a= (v -u)/t
where v is the final velocity
u is the initial velocity
and t is the time frame in which change takes place
Now the data given to us is as follows:
Force F= 15 Newton
initial velocity u =1.2 m/s
t= 2 seconds
We are required to find the final velocity v
Now putting the values in the equation,
F= m (v-u)/t
15 = 7.5 (v-1.2)/2
30= 7.5v -9
7.5v=39
v=39/7.5= 5.2 m/s
Hence the velocity is 5.2m/s
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A reconnaissance plane flies 578 km away from
its base at 360 m/s, then flies back to its base
at 540 m/s.
What is its average speed?
Answer in units of m/s.
Considering the definition of speed, the average speed is 431.94 m/s.
Definition of speedSpeed is a physical quantity that expresses the relationship between the space traveled by an object and the time used for it.
In other words, the speed is associated with the change of position of an object in space within a certain amount of time.
The speed can be calculated using the expression:
speed= distance traveled÷ time
Average speed in this caseIn this case, you know that:
A reconnaissance plane flies 578 km away (equal to 578,000 m, being 1 km= 1000 m) from its base at 360 m/s.The reconnaissance flies back to its base at 540 m/s.Replacing in the definition of speed you can calculate the time it takes to fly away and back:
Flies away: 360 m/s= 578,000 m÷ timeFlies back: 540m/s= 578,000 m÷ timeSolving:
Flies away: 360 m/s× time= 578,000 m → time= 578,000 m÷ 360 m/s → time= 1,605.55 secondsFlies back: 540m/s= 578,000 m÷ time → time= 578,000 m÷ 540 m/s → time= 1,070.77 secondsThen, the total distance traveled and the total time will be the sum of each of the sections traveled:
Total distance traveled= distance to fly away + distance to fly back= 578,000 m + 578,000 m= 1,156,000 mTotal time= time to fly away + time to fly back= 1,605.55 seconds + 1,070.77 seconds= 2,676.32 secondsReplacing in the definition of speed:
speed= 1,156,000 m÷ 2,676.32 s
Solving:
speed= 431.94 m/s
Finally, the average speed is 431.94 m/s.
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While John is traveling along a straight interstate highway, he notices that the mile marker reads 252km. John travels until he reaches the 145km marker and then retraces his path to the 177km marker. What is John's resultant displacement from the 252km marker? Answer in units of km.
John's resultant displacement from the 252km marker when traveling along a straight interstate highway is 75 km
Δx = [tex]x_{2}[/tex] - [tex]x_{1}[/tex]
Δx = Displacement
[tex]x_{2}[/tex] = Final position
[tex]x_{1}[/tex] = Initial position
[tex]x_{2}[/tex] = 177 km
[tex]x_{1}[/tex] = 252 km
Δx = 177 - 252
Δx = - 75 km
Displacement is the shortest distance between initial and final positions. It is denoted using Δx. Since, it is a measure of length, its unit is usually meter.
Therefore, John's resultant displacement from the 252km marker when traveling along a straight interstate highway is -75 km
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Hello what is U ? [tex]V=\frac{U}{q}[/tex]
An ant is crawling along a yardstick that is pointed with the 0-inch mark to the east and the 36-inch mark to the west. It starts at the 17-inch mark, crawls to the 21-inch mark, then moves to the 8-inch mark. What was the total distance the ant traveled?
The total distance that is traveled is 12 inches.
What is the distance?We know that distance is a scalar quantity. The term distance only has to do with the difference between two points. The direction is not taken into cognizance when we are discussing the distance that has been covered.
As we have said that distance is a scalar quantity, it the follows that the process of obtaining the total distance can only be algebraic given that we could directly add all the distance covered by the ant in order to obtain the total distance of the ant.
Now, we can see that the ant starts at the 17-inch mark, crawls to the 21-inch mark, then moves to the 8-inch mark. The total distance covered is obtained from; (21 - 17) + 8 = 12 inches.
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< Question 11 of 27 >
A car traveling 88.0 km/h on a straight road is 2500 m behind a truck traveling at 64.0 km/h.
How much time t will it take the car to catch up with the truck?
t =
A truck moving at 64.0 km/h is 2500 m behind an automobile traveling at 88.0 km/h on a straight route.
How long will it take the automobile to overtake the truck?
Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.
41 kilometers
After a half-hour, the first car is 32.5 kilometers to the north. After a half-hour, the second automobile is 25 kilometers east. You can find out their angular separation from one another using the Pythagorean theorem:
d = √(32.5² +25²) = √1681.25 ≈ 41.00
After a half-hour, the automobiles are around 41 kilometers apart.
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Q1]. An electric field has a magnitude of 400 N/C and makes an angle
60
o
with the perpendicular to the surface of a flat surface of dimensions 30 cm by 20 cm. Calculate the electric flux through the surface.
Q2. Two large horizontal, parallel metal plates are 2.0 cm apart in air and the upper plate is maintained at a positive potential relative to the lower plate so that field strength between them is
2.5x10^5 vm^1.
An electron is released from rest at the lower plate. What is its speed on reaching the upper plate? [e=1.6x10^19 ;me=9.1x10^31kg].
Answer:
An electric field has a magnitude of 400 N/C and makes an angle
60
o
with the perpendicular to the surface of a flat surface of dimensions 30 cm by 20 cm. Calculate the electric flux through the surface.
Explanation:
Which process is a change from gas to liquid?
OA. Freezing
B. Melting
OC. Vaporization
OD. Condensation
Answer:
Condensation
Explanation:
When water vapour (gas) is cooled it undergoes CONDENSATION to form water(liquid).
A force of 30 N is exerted on a wheeled cart. There is so little friction you can
ignore it. The acceleration of the cart is 6 m/s². Find the mass of the cart.
Answer:
force =mass*acceleration due to gravity
mass=force/acceleration
mass =30/6
mass=5kg
Kalea throws a baseball directly upward at time t = 0 at an initial speed of 14.3 m/s. How high h does the ball rise above its release point? Ignore air resistance and use g = 9.80 m/s^2.
The ball reaches a height of 9.57 meters against gravity.
The acceleration an object experiences as a result of gravitational force is known as acceleration due to gravity. M/s2 is its SI unit. Its vector nature—which includes both magnitude and direction—makes it a quantity. The unit g stands for gravitational acceleration. At sea level, the standard value of g on the earth's surface is 9.8 m/s2.
A body is drawn toward the center of the earth by the force of gravity. Let's have a look at two bodies with masses ma and mb. When two bodies are subjected to equal forces, the force in terms of mass is given by:
The inertial mass of a body is defined as mb = ma [aA/aB].
In response to the gravitational pull of two bodies,
FA = GMmA/r2,
FB = GMmB/r2,
mB = [FB/FA] × mA
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In a biathalon race you first ride a bicycle at an average speed of 19.1 mi/h for 18.5 miles, then you must run for another 5.5 miles. With what average speed, in miles per hour, must you run if your average speed for the entire race is to be 14.5 mi/h?
The average speed you must run is 7.97 mph.
What is average speed?The average speed of an object is the ratio of total distance traveled by the object to
Average speed = total distance / total time of motion
Total time of motion = total distance / average speed
total time = (18.5 + 5.5) / (14.5)
total time = 1.66 hours
time taken during the bicycle ridet1 = 18.5 / 19.1
t1 = 0.97 hour
time taken during the runt2 = 1.66 hr - 0.97 hr
t2 = 0.69 hr
Average speed during the runv = 5.5 miles /0.69 hr
v = 7.97 mph
Thus, the average speed you must run is 7.97 mph.
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A crane is used to raise one end of a steel girder off the ground, as shown in Figure 14. When the cable attached to the end of the girder is at 20° to the vertical, the force of the cable on the girder is 6.5 kN. Calculate the horizontal and vertical components of this force. Brider 20% 6.5 KN
The horizontal component of the force of cable is 2.22 kN. The vertical component of the force of cable is 6.1 kN.
If we draw a free body diagram of the force of the cable with its horizontal and vertical components, it will form a right angled triangle.
sin θ = Opposite side / Hypotenuse
cos θ = Adjacent side / Hypotenuse
θ = 20°
Hypotenuse = Force of cable = 6.5 kN
Opposite side = Horizontal component
Adjacent side = Vertical component
sin 20° = Horizontal component / 6.5
Horizontal component = 0.342 * 6.5
Horizontal component = 2.22 kN
cos 20° = Vertical component / 6.5
Vertical component = 6.1 kN
In a right angled triangle, trigonometric ratios can be used as mentioned below.
sin θ = Opposite side / Hypotenusecos θ = Adjacent side / Hypotenusetan θ = Opposite side / Adjacent sideTherefore,
The horizontal component of the force of cable is 2.22 kNThe vertical component of the force of cable is 6.1 kNTo know more about trigonometric ratios
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Explain why a car that was driving along a flat surface and is now heading downhill is not in a closed system?
Since an external force now acts on the car as it moves downhill, it is no longer a closed system.
What is a closed system?A closed system is one in which there is no exchange of energy between the system and the external environment. There is usually a boundary that separates the system from the external environment.
When the car was driving along the flat surface, it could continue moving endlessly according to the Newton's first law of motion. If the direction is now changed downhill, an external force now acts on the car and that is the force of gravity.
Since an external force now acts on the car as it moves downhill, it is no longer a closed system.
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