The velocity of the car moving in the circular path is determined as 1.67 m/s.
What is linear velocity?Linear velocity is the measure of the rate of change of displacement with respect to time when the object moves along a straight path.
v = d/t
where;
d is the distance of the objectt is time of motionv = (6 x 1000 m) / (1 x 3600 s)
v = 1.67 m/s
Thus, the velocity of the car moving in the circular path is determined as 1.67 m/s.
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II Two electrons are in the vicinity of a proton. The potential energy of the
proton is
-1.6 x 10-25 J. (a) What is the potential at the proton's position? (b) If one of
the electrons is 1.0 cm from the proton, what is the distance of the second
electron from the proton?
Please explain HOW to answer this(especially part B)
There are two electrons close to a proton. The proton's potential energy is
the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.
9.216 x 10^-8 N
q1 = 1.6 x 10^-19 C
q2 = - 1.6 x 10^-19 C
r = 5 x 10^-11 m
A source of electrostatic force is
F = k q1 q2 / r^2
F = (5 x 10-11)2 / (9 x 109 x 1.6 x 10-19 x 1.6 x 10-19)
F = 9.216 x 10^-8 N
Due to the nature of the charges being in opposition to one another, this force is appealing.
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2. 100 grams of oil (specific heat capacity 2200 J/kg °C) heated to 80°C are added
to 200 grams of water (specific heat capacity 4200 J/kg °C) at 20°C. Find the
resulting temperature. Assume heat loss to the surroundings is negligible.
100 grams of oil-heated to 80°C are added to 200 grams of water at 20°C. Then the resulting temperature would be 55.48°C.
What is thermal energy?It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.
As given in the problem 100 grams of oil (specific heat capacity 2200 J/kg °C) heated to 80°C is added to 200 grams of water (specific heat capacity 4200 J/kg °C) at 20°C
mCΔT for oil =mCΔT for water
100×2200×(80-T) = 200× 4200×(T-20)
1760-22T = 84 T -1680
62T = 1760+1680
T = 55.48°C
Thus, the resulting temperature of the mixture would be 55.48°C.
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Which is true about mass and weight?
Mass depends on location, weight is the same everywhere.
Mass and weight are the same thing.
Objects dropped in a vacuum (no air) will fall at different rates because they have different weights.
Mass is measured with a spring scale.
Mass must be in kg and weight in N to do our calculations.
The statement that is true about mass and weight is as follows: Mass must be in kg and weight in N to do our calculations (option E).
What is mass and weight?Mass is the quantity of matter which a body contains, irrespective of its bulk or volume. The mass of a substance is measured in kilograms.
On the other hand, weight is the force on an object due to the gravitational attraction between it and the Earth. It is measured in Newtons.
The mass of an object is the same everywhere, however, it's weight is dependent on location. For example, the weight of an apple on Earth will differ from it's weight in Mars.
Therefore, the statement that is true about mass and weight is as follows: Mass must be in kg and weight in N to do our calculations.
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How do ice cubes form in the freezer?
Answer:
In a freezer, the air molecules absorb energy from the water, causing the water molecules to freeze into a solid.
Answer: Water expands when it freezes. As freezing continues, the expanding ice under the surface forces the remaining water up through the hole and it freezes around the edge forming a hollow spike
Explanation:
Water expands when it freezes. As freezing continues, the expanding ice under the surface forces the remaining water up through the hole and it freezes around the edge forming a hollow spike. Eventually, the whole thing freezes and the spike is left.
If a satellite orbiting Earth at an orbiting radius (r) has velocity (v). Which represents the velocity if the satellite is moved to an orbital radius or 4r?
If you can, give an explanation so I can learn it.
The velocity, if the satellite moves to an orbital radius of 4r is V/√4
We know that,
V = √ ( G M / r )
where,
V = Orbital velocity
G = Gravitational constant
M = Mass of the satellite
r = Radius of the orbit
Given that,
r' = 4r
V' = √ ( G M / r' )
V' = √ ( G M / 4r )
V' = ( 1 / √ 4 ) ( √ ( G M / r ) )
v' = v / √ 4
Orbital Velocity is the velocity at which one object revolves around another object in a orbit in uniform circular motion
Therefore, the velocity of the satellite that moved to an orbital radius of 4r is V/√4
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. Which of the following is the last part of the technological design process? test and evaluate a solution research existing solutions refine the original solution design decide on a solution
According to the research, the correct option is to refine the original solution design. It is the last part of the technological design process.
What is the technological design process?It is the process and problem solving using design as a methodological strategy that allows identifying and solving a problem through inductive procedures and logical reasoning.
In this sense, the last part of this process includes what refers to the production of a first model of the solution, which is tested to evaluate its performance, the result of this evaluation must influence the modification or refinement of the original solution design that is implemented in the solution of the problem that gave rise to the generation of the project.
Therefore, we can conclude that according to the research, the correct option is to refine the original solution design. It is the last part of the technological design process.
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Sam's mom says: "We're about to eat dinner! Don't go more than a few blocks from home!" Is Sam's mom
more worried about Sam's distance or his displacement? Circle one and explain why you picked it.
Answer:
Displacement
Explanation:
I think Sam's mom isn't worried with how far away he goes, but will be upset if he isn't home fast enough for dinner.
Which circuit is a series circuit ?
Answer:
the right answer is d
Explanation:
A car travels 60 m/s for 60 secs.
Calculate how far it traveled.
The formula for distance = speed * time
60 m/s is the speed.
60 secs is the time.
Fill them in.
distance = 60 * 60
distance = 3600
please give brainliest
Answer:
3600m
Explanation:
s= vt
= 60m/s × 60sec
=3600m
What is the current in the 60.0 Q resistor? 120.0 V O A. 80.0 A B. 2.00 A O C. 1.50 A OD. 12.0 A 60.002 20.0 Q A
2A
Given ,
Resistance=60
V=12
V=IR
I=V/R
I=120/60=2A
The pace at which electrons flow past a location in a complete electrical circuit is defined as current. At its most fundamental, current Means flow.
An ampere (AM-pir), sometimes known as an amp, is the international unit for measuring current. It denotes the number of electrons (also known as "electrical charge") that pass across a location in a circuit over a specific time period.
A current of one ampere indicates that one coulomb of electrons—that is, 6.24 billion billion (6.24 x 1018) electrons—moves across a circuit in one second. The method is comparable to determining how many gallons move through a single spot in a pipe in one minute (gallons per minute, or GPM).
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if sample of silver and lead each had volumes equal to 1ml, which would have the greater mass, and how much would the difference in the masses be?
If sample of silver and lead each had volumes equal to 1ml, Lead would have the greater mass, and the difference in the masses would be around 0.84grams
What do you mean by term mass?The mass of a physical body is a measure of its entire makeup. This also measures inertia, or the body's resistance to acceleration (change in velocity) in the presence of a net force.
The basic mass unit in the SI is the kilogram (kg)
What is the calculation for the given problem?The Density of Silver = 10.5 g / cm^3
The Density of Lead = 11.34 g / cm^3
So the masses given volume of 1 cm^3 is:
mass of Silver = 10.5 grams
mass of Lead = 11.34 grams
So we see that Lead has greater mass for similar volume.
On solving the given problem we get
The difference is
11.34 – 10.5 = 0.84 grams
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explain why the ray does not bend when it enters the semi circular glass block
The ray does not bend when it enters the semi circular glass block - Light ray incident on semicircular block at 90 degrees, therefore there is no change in the direction of ray at P.
Electromagnetic radiation that falls within the region of the electromagnetic spectrum that the human eye can see is known as light or visible light.
Light is electromagnetic radiation that the human eye can perceive. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than around 1 1011 meters, electromagnetic radiation occurs throughout an incredibly broad range of wavelengths.
Light governs our sleep-wake cycle and is crucial to our health and wellbeing. In actuality, "light" that is visible is a type of radiation, which is just energy that moves in the form of electromagnetic waves. It can alternatively be explained as a flow of "wave-packets," or particles, known as photons.
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what is a reference point or reference frame
Which set of labels should be used to correctly complete the atomic model below?
a.
1 - Electron
2 - Nucleus
3 - Neutron
4 - Proton
b.
1 - Proton
2 - Electron
3 - Neutron
4 - Nucleus
c.
1 - Neutron
2 - Proton
3 - Nucleus
4 - Electron
d.
1 - Proton
2 - Neutron
3 - Electron
4 - Nucleus
Answer:
d. 1-proton 2-nuetron 3-electron 4-nucleus
what exactly is science?
( an answer that wld express a physics teacher please :) )
Answer:
he intellectual and practical activity encompassing the systematic study of the structure and behaviour of the physical and natural world through observation and experiment.
A remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure below represents "snapshots" of the car's position at equal 0.5 s time intervals. (Assume the positive direction is to the right. Indicate the direction with the sign of your answer.)
A. The car's average velocity (in m/s) in the interval between t = 1.0 s to t = 1.5 s is 1 m/s
B. The car's acceleration (in m/s²) at t = 1.5 s is 0.4 m/s²
C. The speed of the car is increasing with time
A. How to determine the average velocity between t = 1.0 s to t = 1.5 sTotal time = 1.5 - 1 = 0.5 sTotal distance = 0.9 - 0.4 = 0.5 mAverage velocity =?Average velocity = total distance / total time
Average velocity = 0.5 / 0.5
Average velocity = 1 m/s
B. How to determine the acceleration at t = 1.5 sWe'll begin by calculating the velocity at t = 1.5 s. This can be obtained as follow:
Distance = 0.9 mTime = 1.5 sVelocity =?Velocity = Distance / time
Velocity = 0.9 / 1.5
Velocity = 0.6 m/s
Finally, we shall determine the acceleration . This is shown below:
Time = 1.5 sVelocity = 0.6 m/sAcceleration =?Acceleration = velocity / time
Acceleration = 0.6 / 1.5
Acceleration = 0.4 m/s²
C. How to determine if the speed is increasing or notThe acceleration we calculated above (i.e 0.4 m/s²) is positive. This simply indicates that the speed of the car is increasing.
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Missing part of the question:
(a) What is the car's average velocity (in m/s) in the interval between t = 1.0 s to t = 1.5 s?
(b) Using data from t = 1.0 s to t = 2.0 s, what is the car's acceleration (in m/s2) at t = 1.5 s?
(c) Is the car's speed increasing or decreasing with time?
Montez drives 400 km west to play a gig in Kansas City.
After the gig he drives 200 km east to jam with some
musicians in Columbia. What distance did he cover? What
was his displacement?
Answer:
See below
Explanation:
Distance covered = 400 + 200 = 600 km
displacement = 400 w - 200 e = 200 km west
(Forces and the Laws of Motion pg. 141; Friction) (Problem 4)
A box of books weighing 325 N moves at a constant velocity across the
floor when the box is pushed with a force of 425 N exerted downward at an
angle of 35.2° below the horizontal. Find μk between the box and the floor.
The coefficient of kinetic friction is determined as 0.75.
What is coefficient of friction?
The coefficient of kinetic friction is calculated by applying the newton's second law of motion.
Fsinθ - Ff = ma
where;
Ff is frictional forceθ is angle of applied forceW = mg
where;
m is mass of the boxm = W/g
m = 325/9.8
m = 33.2 kg
425 sin(35.2) - Ff = 33.2a
425 sin(35.2) - μW = 33.2a
at constant velocity, a = 0
425 sin(35.2) - μW= 0
μW = 244.98
μ = 244.98/W
μ = 244.98/325
μ = 0.75
Thus, the coefficient of kinetic friction is 0.75.
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A train changes its velocity from 70km / h to 20km / h in 6 s The distance it covered is:
a) 75.0 m
b) 9.87 m
c) 15.4 m
d) 20.6 m
The distance covered by the train will be 75 meters.
What is the equation of motion?Physics equations called equations of motion describe how a physical system acts in terms of how its motion alters over time.
The equations of motion, which are a group of mathematical functions stated in terms of dynamic variables, provide a more thorough description of how a physical system behaves.
Given that a train changes its velocity from 70km / h to 20km / h in 6 s.
Use the first equation of motion:-
V= U + at
20 = 70 + ( 1 / 600)a
-50 = ( 1 / 600)a
a = -30000
Use another equation of motion:-
V² = u² + 2as
20² = 70² + 2 ( -30000)S
400 - 4900 = -60000S
-4500 = -60000S
S = -4500 / -60000
S = 0.075 KM
S = 75 meters
Therefore, the distance covered by the train will be 75 meters.
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the tension T in Newtons in the string of a yoyo of mass 0.001kg is give by the function of two variables (see equation in photo).
find the approximate change in T if R increases from 4cm to 4.1cm and r increases from 0.8cm to 0.9cm. use your answer to explain if the tension increases or decreases.
The change in the tension if the radii r changes from 4.0 cm to 4.1 cm, and R changed from 0.8 cm to 0.9 cm is negative, therefore, tension reduces.
How can the correct description of the change in the graph of the function be found?
Mass of the yoyo = 0.001 kg
Initial value of the spindle radius, R = 4 cm
Initial length of the radius of the yo–yo, r = 0.8 cm
The final values are;
R2 = 4.1 cm, r2 = 0.9 cm
Which gives;
[tex]T_{r \:R} = \frac{0.001 \cdot g \cdot R }{2 \cdot r^{2} + R^2} [/tex]
Which gives;
[tex]T_{{r _1 \:R _1 }} = \frac{0.001 \times 9.8 \times 0.04 }{2 \times 0.008^{2} + 0.04²} = \frac{49}{216} [/tex]
[tex]T_{{r _2 \:R _2 }} = \frac{0.001 \times 9.8 \times 0.041 }{2 \times 0.009^{2} + 0.041^2} = frac{2009}{9215} [/tex]
Therefore;
[tex] \Delta T_{{r \:R }} = frac{2009}{9215} - \frac{49}{216} = - \frac{17591}{1990440} [/tex]
Given that difference between the final and the initial states is negative, the the value of the tension decreases
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Determine the value of x. A 9.75 B 11 C 22 D 19.5
A. The value of x in the given circular geometry is determined as 9.75.
Value of x in the geometry
The value of x can be calculated by applying the following rules of geometry as shown below.
angle AC = angle at the center
angle at center = twice angle at circumference
147 = 2(6x + 15)
147 = 12x + 30
147 - 30 = 12x
117 = 12x
x = 117/12
x = 9.75
Thus, the value of x in the given circular geometry is determined as 9.75.
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Why does a mirror or glass polished by dry cloth on a dry day soon gets dirty
As per the given question;
On a dry day, a mirror or window polished with a dry cloth quickly develops dust. Dry cloth friction on glass produces charged static electricity, which attracts microscopic non-charged dust particles.
What is static electricity?Static electricity can cause problems or even pose a risk. Your hair standing on end energy can also destroy electronics and cause explosions. However, it can also be a huge asset to modern life when properly managed and manipulated.
When the positive and negative charges are out of balance, static electricity is produced. While electrons like to jump all over the place, protons and neutrons don't move around that much. A negative charge is present when an object (or person) has extra electrons.
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Part A
What is the instantaneous velocity of a freely falling object 5.0 s after it is released from a position of rest?
Express your answer to two significant figures and include the appropriate units.
v=
The instantaneous velocity of a freely falling object is 49.0 m/s
the instantaneous velocity is calculated by the first equation of the motion that is v = u + at here u = initial velocity and a is acceleration and t is time since its freely falling object the acceleration is acceleration due to gravity that is 9.8 m/s and the initial velocity is 0m /s the time given is 5 sec so putting it into equation 0+ 9.8X 5= 49.0 m/s
The instantaneous velocity of an object is the limit of the average velocity as the elapsed time approaches zero, or the derivative of x with respect to t: v ( t ) = d d t x ( t ) . v ( t ) = d d t x ( t ) . Like average velocity, instantaneous velocity is a vector with dimension of length per time.
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Which option best describes the average acceleration from 40 to 70 s?
C. The average acceleration is positive and smaller in magnitude than the initial acceleration.
What is average velocity?Average velocity is defined as the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs.
a = Δv/Δt
where;
Δv is change in velocityΔt is change in timea = (250 - 248) / (70 - 40)
a = 0.067 m/s²
Thus, we can conclude that the average acceleration is positive and smaller in magnitude than the initial acceleration.
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What would decrease the gravitational pull between the sun and Earth?(1 point)
Responses
a. if the sun was twice its size
if the sun was twice its size
b.
if Earth was twice its size
if Earth was twice its size
c. if Earth was closer to the sun
if Earth was closer to the sun
d. if the sun was farther away from Earth
if the sun was farther away from Earth
The gravitational pull between the sun and Earth decreases if the sun was farther away from the earth.
What is Gravitational Force?Any two bodies' gravitational pull on one another is directly proportional to the product of their masses and inversely proportional to the square of their distance from one another.
How do the planets move in relation to the Sun? The planets' orbits around the Sun are maintained by the gravity of the Sun. The Moon orbits the Earth due to the Earth's gravitational pull on the Moon for the same reason. But if the Earth is being drawn to the Sun, why doesn't it fall into it or the Moon strike the Earth?
The cause of this is because Earth moves at a speed that is perpendicular to the Sun's gravitational pull. The planets are thus kept in their designated orbits by the Sun's attraction as well as their sideways motion. Similar to how the Earth orbits the Moon, the Moon does so without touching it.
F=G(M1M2)/R² where,
F denotes gravitational force between two bodies,
R is the distance between two bodies from their center,
M1 denotes mass of first body and,
M2 denotes mass of second body.
So according to the question, if the distance between two bodies will increase, then the gravitational force between them will also decrease.
Hence, if the sun was farther away from earth, then gravitational pull between the sun and earth will decrease.
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find the component form of the vector V (0,1) (6,7/2)
Answer:
I would interpret it to mean:
Vx = (6 - 0) = 6
Vy = (3.5 - 1) = 2.5
or V = (6, 2.5)
V refers to the vector itself and not its relative position in space
Select the correct answer.
A force Fmaking an angle 9 with the horizontal is acting on an object resting on the table. Which statement Is true for the motion of sliding the
object on the table?
• A. It Is Independent of all the forces acting on the object.
O B. It depends only on the forces acting along the x-axis.
O C. It depends only on the forces acting along the y axis.
O D. It depends only on the normal force acting on the object.
O E. It depends only on the frictional force acting on the object.
bgGjzbxvbhijhFgavvBbzvghzjznbbgzgh
Question 4 of 10
Which of the following describes the reactants of a chemical reaction?
OA. The chemicals on the right side of a chemical equation
B. The substances that are formed
OC. The substances that are made
O D. The chemicals on the left side of a chemical equation
The substances that are altered and the chemicals on the right side of a chemical equation are the results of a chemical reaction. B and D are the appropriate choices.
Reactants are the substance(s) in a chemical equation to the left of the arrow. A component that is present at the outset of a chemical reaction is known as a reactant. Products are the substance(s) to the right of the arrow. A substance that remains after a chemical reaction is complete is known as a product. The creation of products from the reaction of two reactants is known as a chemical reaction. The compounds that result from a reaction are called products. The substances that are original materials are the reactants.
On the left side of the reaction are the reactants, and on the right are the products. B and D are the proper choices as a result.
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would anyone be able to help me? I'm struggling with the last 2 parts
The time taken for the train to stop is 8.9 seconds.
The distance traveled by the train during acceleration is 9,984 m.
The distance traveled by the train during deceleration is 17.8 m.
Time taken for the train to stop
Use the following kinematic equation to determine the time taken for the train to stop.
v = u + at
where;
v is the final velocity of the train = 0u is the initial velocity = 4 m/sa is the deceleration = -0.45 m/s²t is time of motion0 = 4 - 0.45t
0.45t = 4
t = 4/0.45
t = 8.89 seconds = 8.9 seconds
Distance traveled by the train during accelerations = ut + ¹/₂at²
where;
t is time of motion = 8 min = 480 secondss = (4)(480) + ¹/₂(0.07)(480)²
s = 9,984 m
Distance traveled by the train during decelerations = ut + ¹/₂at²
s = (4 x 8.9) + ¹/₂(-0.45)(8.9)²
s = (4 x 8.9) - ¹/₂(0.45)(8.9)²
s = 17.8 m
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A 190 g block hangs from a spring with spring constant 9.0 N/m. At t=0s the block is 29 cm below the equilibrium point and moving upward with a speed of 116 cm/s.
What is the block's oscillation frequency?
What is the block's distance from equilibrium when the speed is 57 cm/s ?
What is the block's distance from equilibrium at t = 7.0 s ?
The block's oscillation frequency is 1.1 Hz.
The block's distance from equilibrium when the speed is 57 cm/s is 14.2 cm.
The block's distance from equilibrium at t = 7.0 s is 10.37 cm.
Oscillation frequency of the block
The oscillation frequency of the block is calculated as follows;
f = 1/2π√(k/m)
f = 1/2π √(9/0.19)
f = 1.1 Hz
Angular speed of the blockω = 2πf
ω = 2π x 1.1
ω = 6.91 rad/s
Equation of the block's motionx(t) = A cos(ωt + Φ)
at t = 0, phase constant is calculated asωX sin(Ф) = v
6.91 x 29 sin(Ф) = 116
sin(Ф) = 116/200.39
sin(Ф) = 0.579
Ф = arc sin(0.579)
Ф = 0.62 rad
Amplitude of the wave29 = A cos(6.91 x 0 + 0.62)
29 = A cos(0.62)
29 = A(0.814)
A = 35.63 cm
Distance of the block at given speedwhen the speed is 57 cm/s, the distance of the block is calculated as follows;
ωX sin(Ф) = v
(6.91)X sin(0.62) = 57
X(4.015) = 57
X = 57/4.015
X = 14.2 cm
Distance of the block at given timex(t) = A cos(ωt + Φ)
x(7) = 35.63 cos(6.91 x 7 + 0.62)
x(7) = 10.37 cm
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